Ni hesabu gani formula zake zilikupa shida?

[conductor]

Ni formula ipi hukuwahi kutana nayo kwenye haratakati zako za shule mpaka Chuo?.je ipi hujui matumiz yake?in real life.?

 

[mkombengwa]

Mi zote tuu zilinisumbua hata magazijuto sikuwah kuzijua. Kwa kifupi kipind Cha hesabu iliikuwa Kama naenda kwa ngariba kutahiriwa bila ganzi.

 

[Meneja Wa Makampuni]

Hapana hesabu hapo mkuu, hizo nazo ni hesabu?? 🤔🤔🤔🤔🤔🤔

 

[KENZY]

Naona umeamua kutuwekea sign za Freemason! ,Hizo zote ni signs za Freemason hesabu ni magazijuto tu hizo nyengine ni uchawi.

 

[Freyzem]

 

[Teknocrat]

Haya wale wa hesabu waanzie hapo...

A curve has parametric equations
x = 8e⁻²ᵗ - 4 and y = 2e²ᵗ + 4.
What is dx/dt?

 

[Mokaze]

Haya wale wa hesabu waanzie hapo...

A curve has parametric equations
x = 8e⁻²ᵗ - 4 and y = 2e²ᵗ + 4.
What is dx/dt?

Is it dx/dt or dy/dx ??, if it is dx/dt then the answer is simply, -2(x+4). 🤣

 

[King Kong III]

Shrodinga equation.

 

[Palina]

Daah wanikumbusha BAM [emoji28][emoji28][emoji28][emoji28] nishawai pata tano chini ya mia

hizi mambo za hesabu zina wenyewe[emoji81][emoji81]

 

[CARDLESS]

Differentiation na Integration [emoji119][emoji119]

Mamamaeeee hapo ilinichukua muda kweli kuzielewa..

 

[Citizen B]

Number theory

 

[Teknocrat]

Is it dx/dt or dy/dx ??, if it is dx/dt then the answer is simply, -2(x+4). 🤣

The power doesn't change when you differentiate e²ᵗ.
Since the derivative of e^x is e^x
The derivative of 8e⁻²ᵗ is -2(8)e⁻²ᵗ

dx/dt = -16e⁻²ᵗ

Trick is to stick dx/dt ignore y = 2e²ᵗ + 4.

 

[khamis kilo]

Hizo alama hadi leo hii hazina msaada wowote katika maisha yangu[emoji25]

 

[jathurwa]

Shrodinga equation.

Aseee hii ndio yenyewe kaka. Ni mwendo wa mambo ya psi tu,asee kwenye Kemia wakaigusa kidogo advance sema ndo hivo hawakuipa mkazo. Ila nakubali sana hiyo hesabu .

Sent from my Infinix X688C using JamiiForums mobile app

 

[Akili zangu hazipo sawa]

Calculus acha tyu

 

[Le professel]

I love numbers... How can I be mathematical wizard?
Cc Mokaze

 

[Nazi Ignition]

"Moment of normal distribution" hii kitu ndo kitu ngumu nilowahi kutananayo

 

[Freyzem]

Is it dx/dt or dy/dx ??, if it is dx/dt then the answer is simply, -2(x+4). [emoji1787]

[emoji777]

 

[Mokaze]

[emoji777]

Hapo kwenye x substitute 8e^-2 -4, ni hicho tu ndicho nilichosahau kuweka ili kupata jibu sahihi., lakini hilo ni jibu unsimplified.

Shida watu tumecrame d/dx e^x=e^X bila kujua imekujaje.


X=8e^-2t-4
(X+4)=8e^-2t rearranging

Taking Ln on both sides

Ln(x+4)=Ln8e^-2t=Ln8-2t Lne

d/dt[(X+4)=Ln8e-2t Lne]

1/(x+4)dx=0-2dt
dx/dt= -2(x+4)

Now substitute x=8e^-2t-4 into -2(x+4) for dx/dt., this becomes

dx/dt=-2(8e^-2t-4+4)= -16e^-2t.


Hiyo ndiyo first principle ambayo mtu anatakiwa aijue kabla ya kujua d/dx Ne^ax=Nae^ax.

 

[Mokaze]

View attachment 2018100

The power doesn't change when you differentiate e²ᵗ.
Since the derivative of e^x is e^x
The derivative of 8e⁻²ᵗ is -2(8)e⁻²ᵗ

dx/dt = -16e⁻²ᵗ

Trick is to stick dx/dt ignore y = 2e²ᵗ + 4.

Upo sahihi, jibu langu ni incomplete kwani nilitumia the first principle ku solve na nikasahau kwenye X ku substitute equation yenyewe x=(8e^-2t-4).