Nawaachia Homework wale wa mambo yetu yaleee back in days (still got it?).....!!!!!

[NnyaMbwate]

Mbona makorokocho????

 

[bysange]

Hii kitu nyepesi sana hasa ukiwa na stimu kichwani...

 

[donlucchese]

Hii kitu nyepesi sana hasa ukiwa na stimu kichwani...

Haha solve lolote la order three hapo!

 

[Pilo boy]

chezea maths ww!utalowa mwenyewe.

 

[donlucchese]

chezea maths ww!utalowa mwenyewe.

Ni balaa, haya mambo ni ya wateule tu!

 

[Pascal Mayalla]

View attachment 124731

Du!, mwanangu sisi wengine umetutoa kapa mbaya!.

 

[donlucchese]

Du!, mwanangu sisi wengine umetutoa kapa mbaya!.

Usiwaze mkuu, haya ni kwaajili waliyopitia Advanced Maths

 

[Heaven on Earth]

we subiri tu nideal na hizi Differential Equations halafu baadae utasahihisha

haujamaliza kusolve tu!!!!!!!!

 

[bysange]

Haha solve lolote la order three hapo!

hahahaaaaa mkuu donlucchese nipo tight kidogo ningekushushia mavitu mpaka uchoke chezea mimi weweeeee!

 

[bysange]

haujamaliza kusolve tu!!!!!!!!

hahahaaaaaaa,nahisi peni imeisha wino ameenda azima nchi jirani,ngoja tumuongezee muda...Lol!

 

[Honey Faith]

kiukweli hizo hesabu sijawahi kuziona

 

[mwanamajimbi]

huyu chamtoto mbn.. kitu limits bana!

 

[farkhina]

Subiri ntafute kalamu na karatasi....
Alafu majibu unayajua lakini isijekua wajifanya ticha apa kumbe mahesabu yenyewe huna😛😛😛😛

 

[Kiteitei]

Hivyo ni vitu gani kwanza??!!utadhani kuku karukaruka kwenye karatasi vile...

 

[kyanaKyoMuhaya]

View attachment 124731

Question:
Show that


y=c1sin2x+3cos2x
is a general solution for the differential equation


d2y/dx2+4y=0

Solution:

We have a second order differential equation and we have been given the general solution. Our job is to show that the solution is correct.


We do this by substituting the answer into the original 2nd order differential equation.


We need to find the second derivative of y:


y = c1 sin 2x + 3 cos 2x


First derivative:


dy/dx=2c1 cos 2x−6 sin 2x
Second derivative:


d2y/dx2=−4c1 sin 2x−12 cos 2x
Now for the check step:


LHS=d2y/dx2+4y=[−4c1sin 2x−12 cos 2x]+4(c1sin 2x+3 cos 2x)=0=RHS

 

[Watu8]

haujamaliza kusolve tu!!!!!!!!

Nishasolvu zote ila nashindwa ku-upload majibu...nisaidie nifanyeje?

 

[Watu8]

kiukweli hizo hesabu sijawahi kuziona

Hehehe...ndio uzione sasa mama...hatari tupu!!!

 

[donlucchese]

kiukweli hizo hesabu sijawahi kuziona

mkuu ni differentials hizi, PURE MATHEMATICS

 

[donlucchese]

hahahaaaaa mkuu donlucchese nipo tight kidogo ningekushushia mavitu mpaka uchoke chezea mimi weweeeee!

hahaha mkuu take all the time you can!

 

[donlucchese]

Subiri ntafute kalamu na karatasi....
Alafu majibu unayajua lakini isijekua wajifanya ticha apa kumbe mahesabu yenyewe huna😛😛😛😛

hahaha mi mwenyewe kilaza, lol! af mpe sister hongera jamani!