Msaada wa haraka hii hesabu!!!

[DASA]

Wale wataalam wa hesabu hebu nisaidieni namna ya kusolve hii haraka, nimejaribu njia zote nimeshindwa (Log... etc), sasa sijui ni uzee unanisumbua!!

2[SUP]x[/SUP]=4X

The answer is 4, sasa tatizo ni namna ya kuipata hiyo 4.
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[Said maneno]

2tolee uchekechea wako.we chukua alama ya ukimwi kisha iandike kwa ulalo ndo correct answer.

 

[Husninyo]

Apply logarithm

 

[DASA]

2tolee uchekechea wako.we chukua alama ya ukimwi kisha iandike kwa ulalo ndo correct answer.

Umelaaniwa wewe!

 

[DASA]

2tolee uchekechea wako.we chukua alama ya ukimwi kisha iandike kwa ulalo ndo correct answer.

Huna adabu! kama hujui kaa kimya. hujalazimishwa kujibu.

Na we kama ni mwanafunzi wa chuo, jihesabie umeshadisco kabla hata masomo hayajaanza. shenzi type!.

 

[DASA]

Apply logarithm

Mkuu nimejaribu hivyo, kuna mahali inagoma kabisa. Ukipata muda jaribu.

 

[Husninyo]

Mkuu nimejaribu hivyo, kuna mahali inagoma kabisa. Ukipata muda jaribu.

imegoma wapi? Mbona mi nimeteremka kiulaini.

 

[Kifulambute]

simple xlog2 = 4X then multiply xlog2 by 0, the 0 = 4 kushneyyyyy

 

[Husninyo]

simple xlog2 = 4X then multiply xlog2 by 0, the 0 = 4 kushneyyyyy

acha kupotosha. Dogo sijui kapata fake.

 

[DASA]

imegoma wapi? Mbona mi nimeteremka kiulaini.

weka hadharani basi mkuu.

 

[Kifulambute]

acha kupotosha. Dogo sijui kapata fake.

sasa kwani shida iko wapi hapo wajameni

 

[PakaJimmy]

simple xlog2 = 4X then multiply xlog2 by 0, the 0 = 4 kushneyyyyy

Nachukia sana hesabu, lakini ukifanya hivyo unapata 0 both sides, and not 4

 

[Husninyo]

weka hadharani basi mkuu.

tatizo via mobile nitashindwa kuweka hizo power. Ngoja nijaribu.

 

[Rangi 2]

Did u try to solve graphically as well??

 

[DASA]

Did u try to solve graphically as well??

Sijajaribu! lakini ukiwa chumba cha mtihani kweli utakuwa na muda kufanya hivyo!! assume huna graph paper!

 

[Husninyo]

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

 

[DASA]

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

Heshima mkuu. lakini kwenye red hiyo sheria ni ipi hiyo!!. hiyo Log jinsi ilivyopotea hapo!!.

maana nilitegemea iwe:

LogX=(X-2)Log2
X=2[SUP](X-2)[/SUP] then uendelee kutoka hapo.

Hiyo sheria uliyotumia hapo juu, naomba ifafanue zaidi.

 

[Husninyo]

Heshima mkuu. lakini kwenye red hiyo sheria ni ipi hiyo!!. hiyo Log jinsi ilivyopotea hapo!!.

maana nilitegemea iwe:

LogX=(X-2)Log2
X=2[SUP](X-2)[/SUP] then uendelee kutoka hapo.

Hiyo sheria uliyotumia hapo juu, naomba ifafanue zaidi.

kaka hizo log zote zipo under base 10 sheria ya log base 10 inasemaje?

 

[ndyoko]

kaka hizo log zote zipo under base 10 sheria ya log base 10 inasemaje?

Hapo mie naona kama niko gengeni nanunua nazi, mwe!

 

[DASA]

kaka hizo log zote zipo under base 10 sheria ya log base 10 inasemaje?

Sio ugomvi kaka, tuelimishane tu. kuwa log base 10 sidhani kama ni ishu, hata kama ingekuwa base 2 as long both logs on both sides have the same base.

kwa jinsi ninavyoona hapo hizo log umezicancel hapo kama number, kitu ambacho sidhani kama ni sahihi kwenye sheria za log. ndio mana nikaomba, kifupi sijawahi kuona hiyo kitu.

kama una uwezo zaidi wa kunieleza hiyo sheria nitashukuru. sidhani kama kwenye vitabu ipo.