Swali rahisi,lakini......!

[Aza]

jamani,mbona mnatukata stimu?
agrrrrr

 

[Jaguar]

Let a=b,[multiply both sides by b];ab=b^2(minus a^2 both sides);ab-a^2=b^2-a^2[factor ou the LHS using distributive law and use the difference in square for RHS];a(b-a)=(b-a)(b plus a),divide by (b-a) both sides;a=(b plus a),now remember a=b,then;a=(a plus a) au a=2a,divide by for both LHS and RHS;a/a=2a/a,then 1=2.Hence proven!

follow me but usijaribu kwenye mtihani

 

[IT Guru]

Let a=b,[multiply both sides by b];ab=b^2(minus a^2 both sides);ab-a^2=b^2-a^2[factor ou the LHS using distributive law and use the difference in square for RHS];a(b-a)=(b-a)(b plus a),divide by (b-a) both sides;a=(b plus a),now remember a=b,then;a=(a plus a) au a=2a,divide by for both LHS and RHS;a/a=2a/a,then 1=2.Hence proven!

hehehe imenichukua dakika 5 kudigest hii kitu. Ahsante sana mkuu

 

[Ibrahimovic]

any number power zero = one.
1^0= 1
2^0= 1
therefore 1=2
hence proved.

Yeah, you are right.. Any number powered by zero is equal to one! Lakini one have never ever been equal to two.
(1= 2)!!

 

[Husninyo]

Yeah, you are right.. Any number powered by zero is equal to one! Lakini one have never ever been equal to two.
(1= 2)!!

mambo ya kuprove hayo. Maassumption kibao tunaenda nayo tu hivyohvyo.

 

[Katavi]

Mmmh!! Hapa hapanifai, mambo ya hesabu tena..!!

 

[IT Guru]

Mmmh!! Hapa hapanifai, mambo ya hesabu tena..!!

hehe vipi mkuu una aleji nayo nini?

 

[msadapadasi]

if
(9!^9!)^9! = (9!)^(9!x9!)
and
99! = (99!/9!)(9!)

then
(99!/9!) > (9!x9!)

Therefore
(9!)^99! > (9!^9!)^9!

AAAAH... ACHENI KUZINGUANA HAPA TUMIENI lugha rahisi, wengine ni wadau wa Hongera kwa Kupata Lover (HKL)

 

[IT Guru]

AAAAH... ACHENI KUZINGUANA HAPA TUMIENI lugha rahisi, wengine ni wadau wa Hongera kwa Kupata Lover (HKL)

ehehehe sina mbavu huku.