Msaada wa haraka hii hesabu!!!

Husninyo said:

maujanja au hujaelewa? Nway, ngoja niende internet cafe nikawaandikie njia vizuri.

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Mmh! Mkuu hujafika tu huko internet cafe hadi leo utumwagie hako ka kipengele?

Apply common logarithim, and finish it.

The FaMa said:

Mmh! Mkuu hujafika tu huko internet cafe hadi leo utumwagie hako ka kipengele?

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bado sijafika.

Husninyo said:

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

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Kumbe una ubavu katika mitaa hii...Hongera zako sana 🙂

BAK said:

Kumbe una ubavu katika mitaa hii...Hongera zako sana 🙂

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mbona amekosea? Mathematically logx not= (x-2)log2 b'se x-2 is an xponent. U cant equate logx and (x-2)log2. Labda ingekuwa logx=log2^(x-2). I'll b back later. Ngoja nkwapime wanafunz wangu.

ahsannnntee

Husninyo said:

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

Click to expand...

hv anayesema chora graph ndio utapata jibu lasivyo hakuna jibu lingine.Mmh nadhani uwezo wake wa hesabu bado ni wakukariri tu ....
Mfano:Unaweza kwenda Dar kutoka Arusha kwa kutumia njia zifuatazo:Nchu kavu(Miguu,baiskel,gari n.k) au anga(Ndege,ungo n.k)

hahahaha 2mia 4 figure!

Pia tunaweza tukatumia Archemedes principle, acha niwasiliane na mwalim kihashish, nitalejea kumwaga maujuzi.

Husninyo said:

2logX=(X-2)Log2
X=(X-2)2

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Acha kamba wewe! Umeondoa vipi logarithms hizo?

Husninyo said:

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

Click to expand...

umedanganya, rudi form two, laws of logarithm.

Mzee said:

umedanganya, rudi form two, laws of logarithm.

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Yupo sahihi jamani. Hebu rudieni post zake vizuri.

Jibu halitakuwa 4 bali 0

Sabry001 said:

Jibu halitakuwa 4 bali 0

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Haiwezi kuwa 0 baba

DASA na Husninyo: Shkamooni!

Hii kitu nlishaishahau zamani sana........... Hizi ajira hizi dah!

DASA said:

Haiwezi kuwa 0 baba

2[SUP]x[/SUP]=4X , 2[SUP]0[/SUP]=4(0), 2[SUP]0[/SUP]=1 and 4(0)=0 wapi na wapi.
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2x=4x
2x-4x=0
2x(1-2)
-2x/-2 =0/-2
x=0/-2
x=0
sory nimetumia mobile ila umeelewa.

Husninyo said:

2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

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naona nyota nyota tu hata sielewi.by they way taaluma yangu ni sheria.lol

Sabry001 said:

2x=4x
2x-4x=0
2x(1-2)
-2x/-2 =0/-2
x=0/-2
x=0
sory nimetumia mobile ila umeelewa.

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Hebu angalia vizuri hilo swali. Au labda hiyo mobile yako kama ni kichina. kushoto ni 2 power x

2^x=4x apply log each side log2^x=log4x xlog2=log4+logx xlog2=2log2+logx xlog2-2log2=logx log2(x-2)=logx dividing by log2(x-2) throughout the eqn we obtain 1=logx/log2(x-2) this can also be writen as logxbase2(x-2)=1, into exponential form it will be 2(x-2)^1=x 2(x-2)=x 2x-4=x x=4 ok!

DASA said:

Yupo sahihi jamani. Hebu rudieni post zake vizuri.

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kuna log kazimaliza kisanii

logx=(x-2)log2
amepata

x=(x-2)2....??. How?