Jibu ni 2, tatizo ni njia

[Shakir]

Twende kazi: 2^x=2x
log2^x=log2x
xlog2=log2+logx
xlog2-log2=logx
log2[x-1]=logx dividing by
log2[x-1] throughout we have
1=logx/log2[x-1]
1=logx base 2[x-1] in exp form it is 2[x-1]^1=2(x-1)=x
2x-2=x
x=2 kwishney

Nakuomba kitu kimoja.
Unapokua unazidisha namba/herufi (n) kwenye Logx uiandike n-logx badala ya log xn, lasivyo tunachanganyana mkuu.
Rudia basi ukokotozi hapo juu under this rule!!

 

[NingaR]

Twende kazi: 2^x=2x
log2^x=log2x
xlog2=log2+logx
xlog2-log2=logx
[log2[x-1]=logx dividing by
log2[x-1] throughout we have
1=logx/log2[x-1]
1=logx base 2[x-1] in exp form it is 2[x-1]^1=2(x-1)=x
2x-2=x
x=2 kwishney

kijana tofautisha
log2(x-1) na (x-1)log2
ulikua unatakiwa utumie (x-1)log2 maana ume factor out log2

 

[Mugizi1]

graphical method is suitable in this question bse in this function x=2 and x=1 using other method only one value is obtained

 

[NingaR]

Mbona unaniruka tena??
Si tulikubaliana "trial & error" inahusika hapa mkuu wangu??

mimi binafsi siikubali njia hiyo kwa sababu ni njia ya kubashiri sana, mfano jibu likiwa ni -3.5715 uta try mara ngapi?

 

[Mugizi1]

kijana tofautisha
log2(x-1) na (x-1)log2
ulikua unatakiwa utumie (x-1)log2 maana ume factor out log2

da! Mbona unachunguza hivyo! NI KWeli log2(x-1)=/=(x-1)log2!!

 

[NingaR]

da! Mbona unachunguza hivyo! NI KWeli log2(x-1)=/=(x-1)log2!!

kwahiyo ulikua unataka kutupeleka chaka??

 

[mwanamabadiliko]

Jamani hii ni Differential calculus equation, hakuna graph hapa, graph haisov differential eqn, tusidanganyane. Watu tumepita huko O level, addition math, A level na chuo tumesoma sana hesabu, sasa msitufanye wajinga,. You can not solve for x using exponent or log law becz the eqn is not logarithm neither exponent. Narudia tena this is DE equation. O LEVel ilboru, A Level mzumbe, udsm eng. 4th yr. Tuache ubsh

 

[mwanamabadiliko]

This is Differential equation, law of expont or logarithm cant find the soln. Also u cant solve DE graphically. Ad^2y/dx^2+Bdy/dx+Cy= -2x+2^x where A, B, C= 0

 

[mwanamabadiliko]

This is DE

 

[mwanamabadiliko]

This is DE

 

[Moony]

Hembu tusaidiane kutafuta njia itakayotumika kupata jawabu la 2.

2^x = 2x

(^ = power)

Kwani ni lugha gani hii? kimisri?

 

[NingaR]

This is Differential equation, law of expont or logarithm cant find the soln. Also u cant solve DE graphically. Ad^2y/dx^2+Bdy/dx+Cy= -2x+2^x where A, B, C= 0

halafu ukitoka hapo unaendeleaje??? acha maneno wewe hata 2X=1 ni DE kwahiyo haiwezi kua solved graphically?? mkuu kama huna uhakika na kitu bora ukae kimya

 

[Mugizi1]

Jamani hii ni Differential calculus equation, hakuna graph hapa, graph haisov differential eqn, tusidanganyane. Watu tumepita huko O level, addition math, A level na chuo tumesoma sana hesabu, sasa msitufanye wajinga,. You can not solve for x using exponent or log law becz the eqn is not logarithm neither exponent. Narudia tena this is DE equation. O LEVel ilboru, A Level mzumbe, udsm eng. 4th yr. Tuache ubsh

Acha ushamba dogo,sasa nani kakuambia ututajie hayo yote.wengine humu tuna Msc(mathematics).usikalili ,uko sahihi lakini haimanishi kwamba ndio njia pekee.

 

[NingaR]

Jamani hii ni Differential calculus equation, hakuna graph hapa, graph haisov differential eqn, tusidanganyane. Watu tumepita huko O level, addition math, A level na chuo tumesoma sana hesabu, sasa msitufanye wajinga,. You can not solve for x using exponent or log law becz the eqn is not logarithm neither exponent. Narudia tena this is DE equation. O LEVel ilboru, A Level mzumbe, udsm eng. 4th yr. Tuache ubsh

naanza kupata mashaka na upeo wako kimahesabu, siku zote mathematicians hua hatubishi kwa kutema povu kama wewe hua tuna bisha kimathematics zaidi, lakini nacho kiona kwako unatema povu tu na kutulazimisha kua lazima tutumie DE techniques, nimekuuliza kua 2x=1 sio DE?? umeshindwa nijibu una bwabwaja tu, alafu eti wewe ndo engineer?? nyie ndo mnatujengea miundombinu mibovu na kula fedha za wa TZ. wewe sio mathematician wala huna hata element moja ya umathematician. unatakiwa,ubadirike and start to act like a real one sio una bwanwaja tu

 

[mwanamabadiliko]

[ [/color]

Basi kaka ka we una msc.maths usingeweza kujiingiza ktk mjadala wa hesabu ambayo haiexist, hili swali halipo ktk kitabu chochote duniani, hili swali toka 2001 naliona kwa watu na wala sio vitabuni. Na nauhakika atakayepata solution basi atakuwa amegundua math formula mpya mana hizi za kwetu zinafeli

 

[mwanamabadiliko]

The existing laws of maths seems to fail in finding the solution of this eqn, inabidi tukae chin tu invent method of solving this, bcoz it does not exist

 

[Mugizi1]

Basi kaka ka we una msc.maths usingeweza kujiingiza ktk mjadala wa hesabu ambayo haiexist, hili swali halipo ktk kitabu chochote duniani, hili swali toka 2001 naliona kwa watu na wala sio vitabuni. Na nauhakika atakayepata solution basi atakuwa amegundua math formula mpya mana hizi za kwetu zinafeli

kwahiyo wewe umesoma vitabu vyote duniani? Generalization!!!

 

[Mugizi1]

Basi kaka ka we una msc.maths usingeweza kujiingiza ktk mjadala wa hesabu ambayo haiexist, hili swali halipo ktk kitabu chochote duniani, hili swali toka 2001 naliona kwa watu na wala sio vitabuni. Na nauhakika atakayepata solution basi atakuwa amegundua math formula mpya mana hizi za kwetu zinafeli

kwahiyo wewe umesoma vitabu vyote vya math duniani? Generalization!!!

 

[NingaR]

Basi kaka ka we una msc.maths usingeweza kujiingiza ktk mjadala wa hesabu ambayo haiexist, hili swali halipo ktk kitabu chochote duniani, hili swali toka 2001 naliona kwa watu na wala sio vitabuni. Na nauhakika atakayepata solution basi atakuwa amegundua math formula mpya mana hizi za kwetu zinafeli

Mkubwa sema una bisha tu, njia ya graph inaleta jibu tena majibu yote mawili just fanya as nilivyo fanya mimi hapo juu utaona kua ina leta majibu,

Mimi bado hata Bachelor degree sijapata lakina wewe ulie nitangulia inaonekana dhahiri kua ume base katika vitabu wala hujaribu kushughulisha akili yako(NO OFFENCE)

 

[Shakir]

The existing laws of maths seems to fail in finding the solution of this eqn, inabidi tukae chin tu invent method of solving this, bcoz it does not exist

Kaka,
Hili swali ni modification tu ya maswali ya log ya kawaida.
Mfano lingeweza kua kama ifuatavyo, na nadhani mtoa swali ametoholea humu.
2^x = x^2
Log (2^x) = Log (x^2)
xlog2 = 2logx
x/logx = 2/log
x=2

Nimetoa mfano tu.
Point yangu ni kua kama the above inewezekana, basi hata 2^x = 2x can also be possible.


Sidhani kama kuna hesabu ambayo haipo popote duniani, kwamba haipo kwenye topic yoyote, sidhani.

Maana kujua tu kwamba x =1 or 2 means ni valid question.