Jibu ni 2, Tatizo ni NJIA. | JamiiForums | The Home of Great Thinkers

# Jibu ni 2, Tatizo ni NJIA.

Discussion in 'Jukwaa la Elimu (Education Forum)' started by Shakir, Sep 12, 2012.

1. ### ShakirJF-Expert Member

#1
Sep 12, 2012
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Hembu tusaidiane kutafuta njia itakayotumika kupata jawabu la 2.

2^x = 2x

(^ = power)

2. ### fidelis zul zoranderJF-Expert Member

#2
Sep 12, 2012
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Ata moja ni jibu..

3. ### King Kong IIIJF-Expert Member

#3
Sep 12, 2012
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Aply log on both side

Xlog2=log2+logx
Xlog2-log2=logx
log2(x-1)=logx
Aya endelea sasa

4. ### Mbwiga88JF-Expert Member

#4
Sep 12, 2012
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hapo ni Trial and Error method jibu ni 2 or 1

5. ### NingaRJF-Expert Member

#5
Sep 12, 2012
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toka nianze kusoma Mathematics sijawahi kutana na swali la mtindo huu yaani power ni function pia vilevile function iko katika terms, hapo mzee wacha niingie chimbo kwanza

6. ### Msafiri KasianJF-Expert Member

#6
Sep 12, 2012
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hivi hii trial and error nayo inasomwa kwenye hesabu? Nilisoma Advanced Maths lakini sidhani kama niliwahi kusoma hii kitu.

7. ### ShakirJF-Expert Member

#7
Sep 12, 2012
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Endelea wapi wakati umekwama mkuu?
Nasikitika Aza Boy mwenzangu unashindwa hii kitu!!

8. ### ShakirJF-Expert Member

#8
Sep 12, 2012
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Haikubaliki kaka,
Shusha formula hapa tupate jibu

9. ### ShakirJF-Expert Member

#9
Sep 12, 2012
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Sawa,
But inapatikanaje?

10. ### ShakirJF-Expert Member

#10
Sep 12, 2012
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Ndio hili umekutana nalo sasa mkuu wangu.
Tena wewe ndio nlikua nakutaka,
Ulivyokokotoa ile integral calculus nikaingia chimbo kuibuka na hili swali.
Although you are "kichwa" enough but huwezi kupata 100% mkuu, you have to surrender.

#11
Sep 12, 2012
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Jamani naomba leo tumalize mjadala wa hili swali, kwanza muelewe hil sio swali la exponent la o level, kwa wale waliosoma advance watanielewa. Mana hii ni calcus, na ni simpo sana. Swali hili jibu lake lipo ktk eqn. Hakuna njia yoyote ya calculation utasovia na ukapata jibu hata ukitumia log. Labda ufoj kwa kupachka jibu. The SOLUTION: kwanza mtambue hili ni swali la second order non linear differential equation with mixed number. Here it is a.d^2y/dx^2+ b.dy/dx+ky= 2x-2^x. Because coeffnts a,b,k= 0 , the eqn is reduced to 2^x= 2x. Hili swal halwez kutka necta mana ni rahsi , AU Litakuwa marks 1 .one of the easiest 2nd eqn of diffential, pia jibu lake sio 2 kama mnavofkiri, jibu ni interms of y that is the solution of DE. We discused this with my lecturer Dk. MHERE udsm, 2010 during my 2nd yr of eng. Degree. For more info, u can go to see the Dr. In DEPARTMENT OF MATHEMATICS AND COMPUTER SCIENCE

12. ### pretty nJF-Expert Member

#12
Sep 12, 2012
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Aaaaaaaaaagggrrrrrrrr kichwa kinauma, napita tu.

13. ### NingaRJF-Expert Member

#13
Sep 12, 2012
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kijana umenofurahisha sana!!
swali kama hilo lazima utumie graphical method ndo peekeyake italeta jibu.
Anza hivi
2^x=2x
=>2^x-2x=0
hapa functionaly itakua hivi
f(x)=2^x-2x
let f(x)=y
utakua
y=2^x-2x
then make table of values kuanzia x=-4,-3,-2,-1,0,1,2,3na4
then chora graph of y=2^x-2x
kumbuka kua y=f(x)=0
then angalia katika graph yako thamani za x wakati y=0
utaona ziko 2 ambazo n
x=1
x=2
:-X=1 and X=2

natumai umeelewa

14. ### fidelis zul zoranderJF-Expert Member

#14
Sep 12, 2012
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ngoja wa pure waje..me ni bam tu!

15. ### lugano5JF-Expert Member

#15
Sep 12, 2012
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yap.hapo unacancell log base 10
unabaki na 2(x-1)=x
2x-2=x
2x-x=2
x=2

16. ### QUALIFIEDJF-Expert Member

#16
Sep 12, 2012
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log 2 na log x zinaisha vp mkuu mbona zinabaki hata kama zote zina base 1

17. ### King Kong IIIJF-Expert Member

#17
Sep 12, 2012
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Mkuu mbona ishakwisha hapo? Hata Lindugani,Matley au Fuvu alikua hatoi hizo Hesabu kwani anajua mkondo mzima ungepata,hata ukienda kwa mkemia kunywa juice utaona karatasi za miogo watu wameshusha hayo mahesabu...

#18
Sep 12, 2012
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Watz wabish. Hiv unachoraje graph, mana hii si expontial function wala linear fx. Ni mixed, sijawah kuona graph ya mixed fuction, 1 wala mbili sio jibu. Hil swali lina solution na wala si jibu kwa sababu hii ni differential enq. Narudia tena mtaften dk.mahere udsm for more clarification

19. ### RootJF-Expert Member

#19
Sep 12, 2012
Joined: Jan 23, 2012
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