Chemsha bongo

[pakapori]

.

 

[Mgirik]

26 kg

 

[mpiga era]

27 kg


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[Aigoo]

27kg

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[Jereman]

Let
X=SUNGURA
Y=PAKA
Z=MBWA...
Then formulate equestion
X+y=10,
X+z=20,
Z+y=24

From first equetion,make x sec subject. ..then
X=10-y then substitute into sec equestion
(10-y)+z=20
Z+y=24

Z-y=10
Z+y=24......then solve simultaneous equestion. ..
You will get
Y=7
Z=17
X=3

Then the total weight of mbwa,sungura,na paka. ..
X+y+z=27
----------------






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[Heneriko]

30 kg

 

[Mshuza2]

Let
X=SUNGURA
Y=PAKA
Z=MBWA...
Then formulate equestion
X+y=10,
X+z=20,
Z+y=24

From first equetion,make x sec subject. ..then
X=10-y then substitute into sec equestion
(10-y)+z=20
Z+y=24

Z-y=10
Z+y=24......then solve simultaneous equestion. ..
You will get
Y=7
Z=17
X=3

Then the total weight of mbwa,sungura,na paka. ..
X+y+z=27
----------------






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Dah kichwa kinauma...

 

[Foxhound]

30kgs

ᴾᵘⁿⁱˢʰ ᵒⁿˡʸ ʰᵉ ʷʰᵒ ᶜᵒᵐᵐⁱᵗᵗᵉᵈ ᵗʰᵉ ᶜʳⁱᵐᵉ✓

 

[Rolence]

Sungura kg3+paka kg7= kg 10
Mbwa kg 17+sungura kg3=kg20
Mbwa kg17+paka kg7=kg24
Sungura+paka+mbwa=?
Kwahiyo 3+7+17= kg27