Only Mathematician Engineering.. Determine the values of x and y...

Only Mathematician Engineering.. Determine the values of x and y...

Jambazi

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SOLUTION


Since angle BCD=124°

angle<ACB = 180-124=56°


angle <ACB=56°

Since line AC= line BC
Then <CAB= <ABC

Recall angle ACB = angle ABC=124°
Then angle CAB =62°
angle ABC =62°


from angle CAB=2X°

2X°=62°
X=31

From angle ABC=(14Y+6)°
( 14Y+6)°=62°

14Y=62-6

14Y=56


Y=4



ANSWERS X=31 ,Y=4
========


Awali ya yote pembetatu ABC ni pacha hivyo Pembe A=Pembe B 2x=14y + 6-----------(i) Mstari mnyoofu ACD una nyuzi 180 Pembe C ya pembetatu ABC= 180-124 Pembe C= 56 Pembe tatu ABC ina jumla ya nyuzi 180 Pembe A + pembe B + Pembe C= 180 2x + 14y + 6 + 56= 180 2x + 14y= 180-62 2x + 14y=118-----------(ii) Solving eqn i and II simultaneously 2x-14y=6 2x+14y=118 By adding the two eqns 4x=124 Divide by 4 both sides x=31 From eqn i 2x=14y+6 2(31)=14y+6 62-6=14y 14y=56 Divide by 14 both sides y=4 Kwa hiyo x ni nyuzi 31 na y ni nyuzi 4 Sektyu vere mache for ur attention
 
SOLUTION


Since angle BCD=124°

angle<ACB = 180-124=56°


angle <ACB=56°

Since line AC= line BC
Then <CAB= <ABC

Recall angle ACB = angle ABC=124°
Then angle CAB =62°
angle ABC =62°


from angle CAB=2X°

2X°=62°
X=31

From angle ABC=(14Y+6)°
( 14Y+6)°=62°

14Y=62-6

14Y=56


Y=4



ANSWERS X=31 ,Y=4




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