mathsjery
JF-Expert Member
- Sep 26, 2015
- 2,208
- 1,755
Take the following IPv4 address: 128.32.10.1
This address has 4 octets where each octet is a single byte (or 8 bits).
Because the above IP address has 32 bits, we can represent it as the unsigned 32 bit number: 2149583361.
HAPA: Naamini tunafahamu mchezo wa ip address na data types in programming, Anasema,
Complete the function that takes an unsigned 32 bit number and returns a string representation of its IPv4 address
This address has 4 octets where each octet is a single byte (or 8 bits).
- 1st octet 128 has the binary representation: 10000000
- 2nd octet 32 has the binary representation: 00100000
- 3rd octet 10 has the binary representation: 00001010
- 4th octet 1 has the binary representation: 00000001
Because the above IP address has 32 bits, we can represent it as the unsigned 32 bit number: 2149583361.
HAPA: Naamini tunafahamu mchezo wa ip address na data types in programming, Anasema,
Complete the function that takes an unsigned 32 bit number and returns a string representation of its IPv4 address