Math challenge

Math challenge

Sawa
Kama vipi shusha nondo hapa tupate jibu.
(sin(78°)/sin(18°)) x (sin(24°)/sin(18°)) x (sin(DBA)/sin(DBC)) = 1

sin(78°) approx 0.9781,
sin(18°) approx 0.3090
sin(24°) approx 0.4067

0.9781/0.3090 approx 3.165
0.4067/0.3090 approx 1.316

3.165 × 1.316 approx 4.166

4.166 × sin(DBA)/sin(DBC) = 1

sin(DBA)/sin(DBC) approx 0.24

Let angle DBA = y, then angle DBC = 42° - y

sin(y)/sin(42°- y) approx 0.24

Solving numerically, let's try y = 8°
sin( 8°) approx 0.1392, sin(34°) approx 0.5582

0.1392/0.5582 approx 0.249 (close to 0.24)

So, angle DBA approx 8 and angle DBC approx 34

Angle ADB = 180° - 78° - 8° = 94°

Angle ADC + angle ADB + angle BDC = 360°
Angle BDC = 360° - 144° - 94° = 122°
x = 122°
 
(sin(78°)/sin(18°)) x (sin(24°)/sin(18°)) x (sin(DBA)/sin(DBC)) = 1

sin78° approx 0.9781,
sin(18°) approx 0.3090
sin24° approx 0.4067

0.9781/0.3090 approx 3.165
0.4067/0.3090 approx 1.316

3.165 × 1.316 approx 4.166

4.166 × sin(DBA)/sin(DBC) = 1

sin(DBA)/sin(DBC) approx 0.24

Let angle DBA = y, then angle DBC = 42° - y

sin(y)/sin(42°- y) approx 0.24

Solving numerically, let's try y = 8°
sin( 8°) approx 0.1392, sin(34°) approx 0.5582

0.1392/0.5582 approx 0.249 (close to 0.24)

So, angle DBA approx 8 and angle DBC approx 34

Angle ADB = 180° - 78° - 8° = 94°

Angle ADC + angle ADB + angle BDC = 360°
Angle BDC = 360° - 144° - 94° = 122°
x = 122°
Ebwana eeh! 🫡
 
Challenge ya kufunga siku.. Wakali wa vibox uwanja wenu huu.
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