Hapa sasa wanamahesabu

Hapa sasa wanamahesabu

Kelvin Joseph

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Wanahesabu wanadai eti 2=1!
Wanasema ikiwa x=y
Basi 2x-x=2y-y
Na 2x-2y=x-y
2(x-y)=x-y 2(x-y)/(x-y)=x-y/x-y2=1
Ona unavyotoa macho! Hauelewi chochote!
 
hiyo assumption ya x ni sawa sawa na y imetoka wapi...,,but anyway,, jukwaa la jox, so naweza nikakubaliana na wewe kwamba huu ni utani
 
something tells me kevin Joseph unafujo sana humu ndani ya jamvi.
 
hyo hesab co... Jst wtchot
if x=y then,
2x-2y=0 and x-y=0. Thats over... t cnt go fthr
 
Vichwa vimeishachoka na mishemishe na wewe tena unataka utupasue tena vichwa..baadae kidogo mimi natoka
 
hyo hesab co... Jst wtchot
if x=y then,
2x-2y=0 and x-y=0. Thats over... t cnt go fthr

Kwani kuna ugumu gani kuandika neno zima? Kwanini kuwapa adhabu wasomaji wa mawazo yako na kuanza "kudhania" hapa ulikuwa na maana fulani.
 
Alternative way
Let a=b
[multiply both sides by b];
ab=b^2
(minus a^2 both sides);
ab-a^2=b^2-a^2
[factor out the LHS using distributive law and use the difference in square for RHS];
a(b-a)=(b-a)(b + a)
divide by (b-a) both sides;
a=(b + a),
now remember
a=b
then;
a=(a + a)
au a=2a,
divide by a for both LHS and RHS;
a/a=2a/a,
then 1=2
 
Alternative way

Angalia hii!
Let a=b, upo sawa
then ab=b^2, it's ok
ab-a^2=b^2-a^2, true.
Olso a(b-a)=(b-a)(b+a) it's ok!

But, u can't divide throughout by (b-a) since a=b, then b-a=0. So the equation is meaningless since you are trying to dived by zero. Kwahiyo basi, moja haiwezi kuwa sawa na mbili hata mwisho wa dunia!!
 
Angalia hii!
Let a=b, upo sawa
then ab=b^2, it's ok
ab-a^2=b^2-a^2, true.
Olso a(b-a)=(b-a)(b+a) it's ok!

But, u can't divide throughout by (b-a) since a=b, then b-a=0. So the equation is meaningless since you are trying to dived by zero. Kwahiyo basi, moja haiwezi kuwa sawa na mbili hata mwisho wa dunia!!

A number devide by zero is not meaningless,it i infinity
 
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