Hivi katibu wa CCM yumo humu jamvini? Hata kama yumo hii si taarifa rasmi. Mwandikieni barua rasmi mkimueleza hoja zenu.
Hivi katibu wa CCM yumo humu jamvini? Hata kama yumo hii si taarifa rasmi. Mwandikieni barua rasmi mkimueleza hoja zenu.Mara zote matarajio ya mtumishi hasa pale uongozi mpya unapoingia madarakani huwa ni positive. Kipindi cha Benno Malisa tulikuwa tunapata mishahara kwa wakati. Sadifa alikuwa anachelewa 10-15 days then tunapata mishahara. Sasa Kheri tokea aingie madarakani ni zaidi ya miezi 9 sasa, hali yetu inakuwa mbaya as days goes on. Ninapoandika uzi huu ni zaidi ya miezi mitatu sasa hatujalipwa. Sasa sijui anategemea tutaishi vipi wakati yeye anazunguka nchi nzima kufanya ziara ambazo hata impact zake hatuzioni.
Dr. Bashiru tafadhali tusaidie katika hili. tuna familia, watoto, ndugu na majamaa wanaotutegemea. Na wengine tunasomesha watoto. Tunaomba utusaidie katibu Mkuu. hali ya maisha ni ngumu sana, tunaomba utuokoe
Hesabu za Polepole hizi akifafanua T1.5 akasema ilikuwa haijaiva wakaila mapema kabla haijakomaa. Hata huyo mwenyekiti wao anazunguka mikoani kula mishahara yao kwakuwa haijaivawatumie njia hii kuzisoma
For example, starting with f0(n) = n + 1:
- f1(n) = f0n(n) = n + n = 2n
- f2(n) = f1n(n) = 2nn > (2 ↑) n for n ≥ 2 (using Knuth up-arrow notation)
- f3(n) = f2n(n) > (2 ↑)n n ≥ 2 ↑2 n for n ≥ 2.
- fk+1(n) > 2 ↑k n for n ≥ 2, k < ω.
- fω(n) = fn(n) > 2 ↑n – 1 n > 2 ↑n − 2 (n + 3) − 3 = A(n, n) for n ≥ 2, where A is the Ackermann function (of which fω is a unary version).
- fω+1(64) > fω64(6) > Graham's number (= g64in the sequence defined by g0 = 4, gk+1 = 3 ↑gk 3).
- This follows by noting fω(n) > 2 ↑n – 1 n> 3 ↑n – 2 3 + 2, and hence fω(gk + 2) > gk+1 + 2.
- fω(n) > 2 ↑n – 1 n = (2 → n → n-1) = (2 → n → n-1 → 1) (using Conway chained arrow notation)
- fω+1(n) = fωn(n) > (2 → n → n-1 → 2) (because if gk(n) = X → n → k then X → n → k+1 = gkn(1))
- fω+k(n) > (2 → n → n-1 → k+1) > (n → n → k)
- fω2(n) = fω+n(n) > (n → n → n) = (n → n → n→ 1)
- fω2+k(n) > (n → n → n → k)
- fω3(n) > (n → n → n → n)
- fωk(n) > (n → n → ... → n → n) (Chain of k+1 n's)
- fω2(n) = fωn(n) > (n → n → ... → n → n) (Chain of n+1 n's)
Mbona unahasira namna hiyo nn shida unapenda sana wenzio wanapotesekaToka enzi za malisa umeajiriwa uvccm mapak sasa bado upo basi wew unamatatizo ama ni mzito ama umebweteka wewe acha aendelee kubana upate akili ya kufanya inshu ingne
Akiuliza tu anatimuliwaKwani uongozi wenu wamesemaje?
Mbona lemutuz ni uvccm je ana miaka 27Uvccm ni ya vijana below 30 by age ..Sasa nyie majukumu ya wababa ambao sio vijana mmeyatoa wapi..eti mna somesha,Khaaa sisi humu uvccm tunajua wote hatuna watoto wala hatutegemewi ndio maana hata boss Hana muda wa kutulipa,anajua tunakula,kuoga,kulala home.
Mtu mwenye majukumu ya ku somesha na wategemezi kibao hawezi bweteka kufanya Kazi uvccm ,lazima uwe na Kazi Yako ,uvccm ni ziada tuuu.pambaneni na Hali Zenu nyie uvccm .
Mkuu hapa umewapotezawatumie njia hii kuzisoma
For example, starting with f0(n) = n + 1:
- f1(n) = f0n(n) = n + n = 2n
- f2(n) = f1n(n) = 2nn > (2 ↑) n for n ≥ 2 (using Knuth up-arrow notation)
- f3(n) = f2n(n) > (2 ↑)n n ≥ 2 ↑2 n for n ≥ 2.
- fk+1(n) > 2 ↑k n for n ≥ 2, k < ω.
- fω(n) = fn(n) > 2 ↑n – 1 n > 2 ↑n − 2 (n + 3) − 3 = A(n, n) for n ≥ 2, where A is the Ackermann function (of which fω is a unary version).
- fω+1(64) > fω64(6) > Graham's number (= g64in the sequence defined by g0 = 4, gk+1 = 3 ↑gk 3).
- This follows by noting fω(n) > 2 ↑n – 1 n> 3 ↑n – 2 3 + 2, and hence fω(gk + 2) > gk+1 + 2.
- fω(n) > 2 ↑n – 1 n = (2 → n → n-1) = (2 → n → n-1 → 1) (using Conway chained arrow notation)
- fω+1(n) = fωn(n) > (2 → n → n-1 → 2) (because if gk(n) = X → n → k then X → n → k+1 = gkn(1))
- fω+k(n) > (2 → n → n-1 → k+1) > (n → n → k)
- fω2(n) = fω+n(n) > (n → n → n) = (n → n → n→ 1)
- fω2+k(n) > (n → n → n → k)
- fω3(n) > (n → n → n → n)
- fωk(n) > (n → n → ... → n → n) (Chain of k+1 n's)
- fω2(n) = fωn(n) > (n → n → ... → n → n) (Chain of n+1 n's)
huyo kijana kapambana sana enza za kina faizafox naona awamu hii mkuu hakumbuki kizazi cha kikweteNani kakuambia utoe siri za ndani? wewe lazima unatumiwa!
ina maana hukuwaona kwenye sherehe za mei mosi wakiandamanaKwani UVCCM mnafanya kazi gani mpaka mpewe mshahara.....mnazalisha nn...hiyo pesa ya mishahara inatoka wapi
wasisahau kuintegrate cosine thetawatumie njia hii kuzisoma
For example, starting with f0(n) = n + 1:
- f1(n) = f0n(n) = n + n = 2n
- f2(n) = f1n(n) = 2nn > (2 ↑) n for n ≥ 2 (using Knuth up-arrow notation)
- f3(n) = f2n(n) > (2 ↑)n n ≥ 2 ↑2 n for n ≥ 2.
- fk+1(n) > 2 ↑k n for n ≥ 2, k < ω.
- fω(n) = fn(n) > 2 ↑n – 1 n > 2 ↑n − 2 (n + 3) − 3 = A(n, n) for n ≥ 2, where A is the Ackermann function (of which fω is a unary version).
- fω+1(64) > fω64(6) > Graham's number (= g64in the sequence defined by g0 = 4, gk+1 = 3 ↑gk 3).
- This follows by noting fω(n) > 2 ↑n – 1 n> 3 ↑n – 2 3 + 2, and hence fω(gk + 2) > gk+1 + 2.
- fω(n) > 2 ↑n – 1 n = (2 → n → n-1) = (2 → n → n-1 → 1) (using Conway chained arrow notation)
- fω+1(n) = fωn(n) > (2 → n → n-1 → 2) (because if gk(n) = X → n → k then X → n → k+1 = gkn(1))
- fω+k(n) > (2 → n → n-1 → k+1) > (n → n → k)
- fω2(n) = fω+n(n) > (n → n → n) = (n → n → n→ 1)
- fω2+k(n) > (n → n → n → k)
- fω3(n) > (n → n → n → n)
- fωk(n) > (n → n → ... → n → n) (Chain of k+1 n's)
- fω2(n) = fωn(n) > (n → n → ... → n → n) (Chain of n+1 n's)
Utukufu wa Mungu ni wa ajabu sana !Mara zote matarajio ya mtumishi hasa pale uongozi mpya unapoingia madarakani huwa ni positive. Kipindi cha Benno Malisa tulikuwa tunapata mishahara kwa wakati. Sadifa alikuwa anachelewa 10-15 days then tunapata mishahara. Sasa Kheri tokea aingie madarakani ni zaidi ya miezi 9 sasa, hali yetu inakuwa mbaya as days goes on. Ninapoandika uzi huu ni zaidi ya miezi mitatu sasa hatujalipwa. Sasa sijui anategemea tutaishi vipi wakati yeye anazunguka nchi nzima kufanya ziara ambazo hata impact zake hatuzioni.
Dr. Bashiru tafadhali tusaidie katika hili. tuna familia, watoto, ndugu na majamaa wanaotutegemea. Na wengine tunasomesha watoto. Tunaomba utusaidie katibu Mkuu. hali ya maisha ni ngumu sana, tunaomba utuokoe