Maths Quiz: Tafuta eneo lililotiwa kivuli

Maths Quiz: Tafuta eneo lililotiwa kivuli

WA-UKENYENGE

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Find the area of the shaded region!!
 
Find area of the whole figure which is a triangle (56*42*0.5) and a semi circle (35*35*22/7) the total will be 3101 cm square. From this minus the unshaded part which is a quarter of a circle (22/7*42*42*0.5) which is 1386 cm squire. You will remain with 1715 cm squire.
 
1.Find the area ya Nusu Duara(AC)
2.Find the area of Triangle(ABC)
3.Total Area=AC+ABC
4.Find Area of Quarter Circle(BC)
5.Shaded Area=Total-BC

My worry hapo hakuna semi circle wala quarter circle - naona arc na parabolic shape (not really a semi circle tafuta centre ya hypotenuse halafu piga bikari utanielewa)!
 
My worry hapo hakuna semi circle wala quarter circle - naona arc na parabolic shape (not really a semi circle tafuta centre ya hypotenuse halafu piga bikari utanielewa)!

are you really serious? umeshindwa hata kufuatisha hizo point jamaa alizozibainisha....
jaribu kukumbuka hesabu za maumbo STD 6 wala akili yako usiipeleke kwenye Adv. maths, hivyo unavyoviona vipo lakini havihusiki
 
Find area of the whole figure which is a triangle (56*42*0.5) and a semi circle (35*35*22/7) the total will be 3101 cm square. From this minus the unshaded part which is a quarter of a circle (22/7*42*42*0.5) which is 1386 cm squire. You will remain with 1715 cm squire.
Did you mean square or squirrel? Anyway, nice try!
 
Soln
Find the area of quartercircle AB
Π×42^2×1/4=1384.74 square cm=Area of unshaded part.
Find length CB=
√(56×56)+(42×42)=70CM.
AREA OF TRIANGLE ABC
56×42×1/2=1176squareCM.
AREA OF HALFCIRCLE BC
Π×35^2=(3846.5+1176)-(1384.74)=
…area of shaded region=(345.086+1176)-(1384.74)=3637.76squareCM
 
Soln
Find the area of quartercircle AB
Π×42×1/4=32.97 square cm=Area of unshaded part.
Find length CB=
√(56×56)+(42×42)=70CM.
AREA OF TRIANGLE ABC
56×42×1/2=1176squareCM.
AREA OF HALFCIRCLE BC
Π×35^2=(3846.5+1176)-(1384.74)=
…area of shaded region=(345.086+1176)-(1384.74)=3637.76squareCM
Dimensionally your solution is invalid! Try again, hapo kwenye red.
 
Find area of the whole figure which is a triangle (56*42*0.5) and a semi circle (35*35*22/7) the total will be 3101 cm square. From this minus the unshaded part which is a quarter of a circle (22/7*42*42*0.5) which is 1386 cm squire. You will remain with 1715 cm squire.
Error noted in finding the area of quarter circle, it should be 22/7*42*42*0.25
 
are you really serious? umeshindwa hata kufuatisha hizo point jamaa alizozibainisha....
jaribu kukumbuka hesabu za maumbo STD 6 wala akili yako usiipeleke kwenye Adv. maths, hivyo unavyoviona vipo lakini havihusiki
You can actually use any approach, sema JF haina option ya kuweka integral symbol na option za kuandika equations!! MODs, tusaidieni kutuwekea hizi symbols za integral na equations watu wajimwage siyo siasa tu!
 
Hii inahusu demographic na mtawanyiko wa watu kwa kuanzia na maeneo ya uzalishaji mkubwa wa ndizi? Au ni mifumo ya kiutawala Duniani......kwamba kwa kadri tunavyoharibu mazingira ndivyo tunavyoifanya dunia yetu kuwa mahali hatari pa kuishi?

Hebu nieleweshe concept ya swali niporomoshe majibu daaadeki
 
Soln
Find the area of quartercircle AB
Π×42^2×1/4=1384.74 square cm=Area of unshaded part.
Find length CB=
√(56×56)+(42×42)=70CM.
AREA OF TRIANGLE ABC
56×42×1/2=1176squareCM.
AREA OF HALFCIRCLE BC
Π×35^2=(3846.5+1176)-(1384.74)=
…area of shaded region=(345.086+1176)-(1384.74)=3637.76squareCM

check kwa makin mkuu.
Mkuu nilikuwa sijakaona kakipeuo! Big up sana!!!
 
Hii inahusu demographic na mtawanyiko wa watu kwa kuanzia na maeneo ya uzalishaji mkubwa wa ndizi? Au ni mifumo ya kiutawala Duniani......kwamba kwa kadri tunavyoharibu mazingira ndivyo tunavyoifanya dunia yetu kuwa mahali hatari pa kuishi?

Hebu nieleweshe concept ya swali niporomoshe majibu daaadeki
Mkuu hii ni part I, tukishapata jibu tutajiuliza maswali kama lako kusogea hatua ya mbele!
 
4th yr, engineering Udsm. The solution: The shaded area = total area- area of quarter circle= ((1/2x BCx AB) + (IIx AC^2)/2) - IIx AC^2/4 = 3100.2255 sqrcm- 1385.4sqrcm= 1714.4855 sqrcm
 
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