WA-UKENYENGE
JF-Expert Member
- Oct 1, 2011
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Find the area of the shaded region!!
1.Find the area ya Nusu Duara(AC)
2.Find the area of Triangle(ABC)
3.Total Area=AC+ABC
4.Find Area of Quarter Circle(BC)
5.Shaded Area=Total-BC
My worry hapo hakuna semi circle wala quarter circle - naona arc na parabolic shape (not really a semi circle tafuta centre ya hypotenuse halafu piga bikari utanielewa)!
Did you mean square or squirrel? Anyway, nice try!Find area of the whole figure which is a triangle (56*42*0.5) and a semi circle (35*35*22/7) the total will be 3101 cm square. From this minus the unshaded part which is a quarter of a circle (22/7*42*42*0.5) which is 1386 cm squire. You will remain with 1715 cm squire.
How did you your answer?1,714.78 sq cm
Dimensionally your solution is invalid! Try again, hapo kwenye red.Soln
Find the area of quartercircle AB
Π×42×1/4=32.97 square cm=Area of unshaded part.
Find length CB=
√(56×56)+(42×42)=70CM.
AREA OF TRIANGLE ABC
56×42×1/2=1176squareCM.
AREA OF HALFCIRCLE BC
Π×35^2=(3846.5+1176)-(1384.74)=
…area of shaded region=(345.086+1176)-(1384.74)=3637.76squareCM
Error noted in finding the area of quarter circle, it should be 22/7*42*42*0.25Find area of the whole figure which is a triangle (56*42*0.5) and a semi circle (35*35*22/7) the total will be 3101 cm square. From this minus the unshaded part which is a quarter of a circle (22/7*42*42*0.5) which is 1386 cm squire. You will remain with 1715 cm squire.
You can actually use any approach, sema JF haina option ya kuweka integral symbol na option za kuandika equations!! MODs, tusaidieni kutuwekea hizi symbols za integral na equations watu wajimwage siyo siasa tu!are you really serious? umeshindwa hata kufuatisha hizo point jamaa alizozibainisha....
jaribu kukumbuka hesabu za maumbo STD 6 wala akili yako usiipeleke kwenye Adv. maths, hivyo unavyoviona vipo lakini havihusiki
Dimensionally your solution is invalid! Try again, hapo kwenye red.
Soln
Find the area of quartercircle AB
Π×42^2×1/4=1384.74 square cm=Area of unshaded part.
Find length CB=
√(56×56)+(42×42)=70CM.
AREA OF TRIANGLE ABC
56×42×1/2=1176squareCM.
AREA OF HALFCIRCLE BC
Π×35^2=(3846.5+1176)-(1384.74)=
…area of shaded region=(345.086+1176)-(1384.74)=3637.76squareCM
Mkuu nilikuwa sijakaona kakipeuo! Big up sana!!!check kwa makin mkuu.
Mkuu hii ni part I, tukishapata jibu tutajiuliza maswali kama lako kusogea hatua ya mbele!Hii inahusu demographic na mtawanyiko wa watu kwa kuanzia na maeneo ya uzalishaji mkubwa wa ndizi? Au ni mifumo ya kiutawala Duniani......kwamba kwa kadri tunavyoharibu mazingira ndivyo tunavyoifanya dunia yetu kuwa mahali hatari pa kuishi?
Hebu nieleweshe concept ya swali niporomoshe majibu daaadeki
Hivi:[(Πx(BA-BC)x(BA+BC))+(4xBCxBA)]/8 where Π=3.1415926536, BA=56cm and BC=42cmHow did you your answer?