Only Mathematician Engineering.. Determine the values of x and y...

x=31, y=3.92



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Awali ya yote pembetatu ABC ni pacha
hivyo Pembe A=Pembe B
2x=14y + 6-----------(i)
Mstari mnyoofu ACD una nyuzi 180
Pembe C ya pembetatu ABC= 180-124
Pembe C= 56
Pembe tatu ABC ina jumla ya nyuzi 180
Pembe A + pembe B + Pembe C= 180
2x + 14y + 6 + 56= 180
2x + 14y= 180-62
2x + 14y=118-----------(ii)
Solving eqn i and II simultaneously

2x-14y=6
2x+14y=118
By adding the two eqns
4x=124
Divide by 4 both sides
x=31
From eqn i
2x=14y+6
2(31)=14y+6
62-6=14y
14y=56
Divide by 14 both sides
y=4
Kwa hiyo x ni nyuzi 31 na y ni nyuzi 4
Sektyu vere mache for ur attention
 
TRUE
 
Solution.

From general equation,

3X-Y=12

let y be 0

Then 3X=12

X=4


Let x be 0

Y=12

Then from the required equation
x
8
_________
y
2

Since X = 4 ,Y =12

8⁴
_______
2¹²

Then

( (2)³)⁴)
___________
(2)¹²


(2)¹²
__________
(2)¹²


=1



So the correct answer is D.




*kaka jambazi* njoo uni correct if am wrong. Dah hizi hesabu nakumbuka nilipokuwa form one nilizipiga sana yaani.
 
Kwa simultaneous equation
Soln:
2x=14y+6 ..... i
since two angles zinafanana

Pia kwa kua tuna mstari unao fanya nyuzi 124 kwenye mstari mnyoofu, hivyo kama zile pembe mbili zinafanana basi inayobaki ya tatu ni 180-124=nyuzi 56

Sasa basi

2x+56+14y+6=180..........ii

X=31 na Y=4

Itufae Shoe Shine
 
Siyo kwelii mkuu

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Serious unasema" Only Mathematician Engineering" kwa hii hesabu ya darasa la 7?
ukapimwe mkojo wewe......nime solve hesabu ngumu sana katika maisha yangu ya shule,... hesabu gani sasa hii
 
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