Jambazi
JF-Expert Member
- Jan 18, 2014
- 16,654
- 18,801
========SOLUTION
Since angle BCD=124°
angle<ACB = 180-124=56°
angle <ACB=56°
Since line AC= line BC
Then <CAB= <ABC
Recall angle ACB = angle ABC=124°
Then angle CAB =62°
angle ABC =62°
from angle CAB=2X°
2X°=62°
X=31
From angle ABC=(14Y+6)°
( 14Y+6)°=62°
14Y=62-6
14Y=56
Y=4
ANSWERS X=31 ,Y=4
Awali ya yote pembetatu ABC ni pacha hivyo Pembe A=Pembe B 2x=14y + 6-----------(i) Mstari mnyoofu ACD una nyuzi 180 Pembe C ya pembetatu ABC= 180-124 Pembe C= 56 Pembe tatu ABC ina jumla ya nyuzi 180 Pembe A + pembe B + Pembe C= 180 2x + 14y + 6 + 56= 180 2x + 14y= 180-62 2x + 14y=118-----------(ii) Solving eqn i and II simultaneously 2x-14y=6 2x+14y=118 By adding the two eqns 4x=124 Divide by 4 both sides x=31 From eqn i 2x=14y+6 2(31)=14y+6 62-6=14y 14y=56 Divide by 14 both sides y=4 Kwa hiyo x ni nyuzi 31 na y ni nyuzi 4 Sektyu vere mache for ur attention
X=31, Y=4
🙂 😀 😱 😳 🙄 😵 Hmm. Sitaki hata kujisumbua, maana naona michoromichoro tu na namba kwa mbaali... Mngeleta mambo ya kisayansi hapa tungeheshimiana...
🙂 😀 😱 😳 🙄 😵 Hmm. Sitaki hata kujisumbua, maana naona michoromichoro tu na namba kwa mbaali... Mngeleta mambo ya kisayansi hapa tungeheshimiana...