The FaMa
Senior Member
- Oct 6, 2011
- 125
- 27
maujanja au hujaelewa? Nway, ngoja niende internet cafe nikawaandikie njia vizuri.
Mmh! Mkuu hujafika tu huko internet cafe hadi leo utumwagie hako ka kipengele?
maujanja au hujaelewa? Nway, ngoja niende internet cafe nikawaandikie njia vizuri.
Mmh! Mkuu hujafika tu huko internet cafe hadi leo utumwagie hako ka kipengele?
2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.
Kumbe una ubavu katika mitaa hii...Hongera zako sana
2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.
Acha kamba wewe! Umeondoa vipi logarithms hizo?2logX=(X-2)Log2
X=(X-2)2
2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.
Haiwezi kuwa 0 baba
2[SUP]x[/SUP]=4X , 2[SUP]0[/SUP]=4(0), 2[SUP]0[/SUP]=1 and 4(0)=0 wapi na wapi.
naona nyota nyota tu hata sielewi.by they way taaluma yangu ni sheria.lol2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.
Yupo sahihi jamani. Hebu rudieni post zake vizuri.