# Msaada wa haraka hii hesabu!!!

Discussion in 'Jukwaa la Elimu (Education Forum)' started by DASA, Oct 4, 2011.

1. ### DASAJF-Expert Member

#1
Oct 4, 2011
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Wale wataalam wa hesabu hebu nisaidieni namna ya kusolve hii haraka, nimejaribu njia zote nimeshindwa (Log... etc), sasa sijui ni uzee unanisumbua!!

2[SUP]x[/SUP]=4X

The answer is 4, sasa tatizo ni namna ya kuipata hiyo 4.

2. S

### Said manenoMember

#2
Oct 4, 2011
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2tolee uchekechea wako.we chukua alama ya ukimwi kisha iandike kwa ulalo ndo correct answer.

3. ### HusninyoJF-Expert Member

#3
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Apply logarithm

4. ### DASAJF-Expert Member

#4
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Umelaaniwa wewe!

5. ### DASAJF-Expert Member

#5
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Huna adabu! kama hujui kaa kimya. hujalazimishwa kujibu.

Na we kama ni mwanafunzi wa chuo, jihesabie umeshadisco kabla hata masomo hayajaanza. shenzi type!.

6. ### DASAJF-Expert Member

#6
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Mkuu nimejaribu hivyo, kuna mahali inagoma kabisa. Ukipata muda jaribu.

7. ### HusninyoJF-Expert Member

#7
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imegoma wapi? Mbona mi nimeteremka kiulaini.

8. K

### KifulambuteJF-Expert Member

#8
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simple xlog2 = 4X then multiply xlog2 by 0, the 0 = 4 kushneyyyyy

9. ### HusninyoJF-Expert Member

#9
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acha kupotosha. Dogo sijui kapata fake.

10. ### DASAJF-Expert Member

#10
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weka hadharani basi mkuu.

11. K

### KifulambuteJF-Expert Member

#11
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sasa kwani shida iko wapi hapo wajameni

12. ### PakaJimmyJF-Expert Member

#12
Oct 4, 2011
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Nachukia sana hesabu, lakini ukifanya hivyo unapata 0 both sides, and not 4

13. ### HusninyoJF-Expert Member

#13
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tatizo via mobile nitashindwa kuweka hizo power. Ngoja nijaribu.

14. R

### Rangi 2Senior Member

#14
Oct 4, 2011
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Did u try to solve graphically as well??

15. ### DASAJF-Expert Member

#15
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Sijajaribu! lakini ukiwa chumba cha mtihani kweli utakuwa na muda kufanya hivyo!! assume huna graph paper!

16. ### HusninyoJF-Expert Member

#16
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2^x =4x......log
log2 ^x=log4x.
Xlog2=log(2^2)X.
Xlog2=log(2^2)+logX.
Xlog2=2log2+logX
logX=Xlog2-2log2
logX=(X-2)Log2
X=(X-2)2
X=2X-4
4=2X-X
X=4.

17. ### DASAJF-Expert Member

#17
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Heshima mkuu. lakini kwenye red hiyo sheria ni ipi hiyo!!. hiyo Log jinsi ilivyopotea hapo!!.

maana nilitegemea iwe:

LogX=(X-2)Log2
X=2[SUP](X-2)[/SUP] then uendelee kutoka hapo.

Hiyo sheria uliyotumia hapo juu, naomba ifafanue zaidi.

18. ### HusninyoJF-Expert Member

#18
Oct 4, 2011
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kaka hizo log zote zipo under base 10 sheria ya log base 10 inasemaje?

19. ### ndyokoJF-Expert Member

#19
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Hapo mie naona kama niko gengeni nanunua nazi, mwe!

20. ### DASAJF-Expert Member

#20
Oct 4, 2011
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