Wajuzi wa hesabu, nisaidieni hii hesabu

Royal Warrior

JF-Expert Member
Nov 19, 2015
1,166
2,143
Swali ni solve by factorizing method.
 

Attachments

  • 1453795801528.jpg
    1453795801528.jpg
    43.1 KB · Views: 38
Divide by 3 throught

K^2 -11k+24=0

K^2-8k-3k+24=0
K(k-8)-3(k-8)=0
(k-3)(k-8)=0

K=3 or 8
 
Mbona ilo suali rahisi,, nilifikiri umetuteg kua b^2 >4ac, kwanza tukuulize, kilichokushinda nini
 
Huyu atakuwa ni form two.

Kamaliza topic ya Numbers,exponent then quadratic baada ya hapo atasoma Radical apige Trigonometritc ratio.Nakuendelea.

Sina lakuongezea maana mkuu Kokotoa amesha kokotoa na kapatia.
 
Divide by 3 through out

k²-11k+ 24=0

k²-8k -3k+ 24= 0

k(k- 8 )- 3(k- 8 )= 0

(k- 3)(k- 8 )= 0

k- 3 = 0 or k- 8 = 0

k= 3 or k= 8.
 
Back
Top Bottom