kwa wale wa mathematics!,

[mnoel]

solve for x,,
2logx=x/25
njia muhimu wakubwa!

 

[mwanamabadiliko]

[QUOTE=mnoel;461877. Jibu ni 100 , hili swali halina njia. Am from UDSM- College of engineering

 

[fortunho]

halaf ndo utakua eng baadae duh.kweli math sio mapishi angalia mie ninavyo kupa njia mbili afu 1 october nakuja hapo hapo.coet na mie ndo nakuja kuanza mwaka wa kwanza chem & prcssn eng.naanza na njia ya kwanza1.umepewa 2logx=x/25.let y=2logx then y=x/25 chora table of result then graph dem af angalia intersection utapata jibu.njia ya pili2.umepewa 2logx=x/25 then 2logx-x/25=0,then let f(x)=y=0,then f(x)=2logx-x/25.chora graph ya f(x) af angalia sehemu katika graph ambapo f(x)=0 it is the answer.note EVERY PROBLEM HAS SOLN or SOLNS

 

[mwanamabadiliko]

OLNS[/QUOTE]. Hongera na karibu coet. Ila coet ukija hiz njia zako feki tupa kule. Swali halina njia .am 4th yr coet

 

[NullPointer]

Jibu ni 100 ila kwa njia ya Trial&Error... Chora table, row ya kwanza 2logx, table ya pili x/25 then kwenye column anza kutumia akili ya kuzaliwa unajaza numbers hadi upate same soln... kwa sasa sina njia nyingine..... Mzumbe High School PCM

 

[Mugizi1]

OLNS

. Hongera na karibu coet. Ila coet ukija hiz njia zako feki tupa kule. Swali halina njia .am 4th yr coet[/QUOTE]

dogo hizo MT ulizosoma hapo coet ndo unaona umesoma kila kitu.course zenyewe sijui kama zinazidi nne halafu ni MT for non major.sijui kama umesoma course ya analysis hata moja dio maana unasema hivi.

 

[Shark]

solve for x,,
2logx=x/25
njia muhimu wakubwa!

I'll be back!!!

 

[QUALIFIED]

umepataje 100 kama hakuna njia?

 

[NingaR]

umepataje 100 kama hakuna njia?

katumia"Trial and Error" Method
teh! teh! teh!

 

[fortunho]

. Hongera na karibu coet. Ila coet ukija hiz njia zako feki tupa kule. Swali halina njia .am 4th yr coet

dogo hizo MT ulizosoma hapo coet ndo unaona umesoma kila kitu.course zenyewe sijui kama zinazidi nne halafu ni MT for non major.sijui kama umesoma course ya analysis hata moja dio maana unasema hivi.[/QUOTE]

you have 2 b srous

 

[Mbwiga88]

hiyo ni differential eqn,...Ilboru 4m 6 PCM

 

[mnoel]

swali lolote lenye jibu lina njia wakubwa!!
Chemsheni ubongo!!

 

[Good Guy]

hiyo ni differential eqn,...Ilboru 4m 6 PCM

wewe acha kuotea vitu na kudanganya umma! Unaweza nambia order ya hiyo eqn if its wat you say it is?

 

[Lugano5]

hilo swali balaa nilienda shule fulani kupiga tempo nikapewa na madogo ila nilifoji njia ikaja 100.....kwani niliona nitadhalilika hapa mjini na ukizingatia nimepga pcm alaf nasoma eng..........

 

[King Kalu G]

solve for x,,
2logx=x/25
njia muhimu wakubwa!

un42natry we dont know x so we cant solve 4 him

 

[Shark]

I'll be back!!!

I am back now!!

2Logx = x/25

Divide by x both sides
(2/X)logx = 1/25

logx [SUP](2/x)[/SUP] = 1/25


Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)

[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]

we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)

[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x

[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x

[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]

x = 100
O-Level, Azania '96 - '99

 

[JOAQUEM]

I am back now!!

2Logx = x/25

Divide by x both sides
(2/X)logx = 1/25

logx [SUP](2/x)[/SUP] = 1/25


Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)

[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]

we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)

[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x

[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x

[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]

x = 100
O-Level, Azania '96 - '99

Good nimekubali

 

[ndetichia]

un42natry we dont know x so we cant solve 4 him

mmmmmhhhhh hiyo lugha jf kazi ipo kwa mamod

 

[Shark]

I am back now!!

2Logx = x/25

Divide by x both sides
(2/X)logx = 1/25

logx [SUP](2/x)[/SUP] = 1/25


Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)

[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]

we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)

[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x

[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x

[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]

x = 100
O-Level, Azania '96 - '99

Aminia mkuu,
Ulivyosema you will be back nlifikiri umeingia mitini!!

 

[ndetichia]

I am back now!!

2Logx = x/25

Divide by x both sides
(2/X)logx = 1/25

logx [SUP](2/x)[/SUP] = 1/25


Remove log sign
10[SUP](1/25) [/SUP]= x[SUP](2/x)

[/SUP]Take √ both sides(but √ means power 1/2)
so, from √10[SUP](1/25) [/SUP]=√x [SUP](2/x)[/SUP]

we will get
10[SUP]1/25(1/2)[/SUP] = x[SUP]2/x(1/2)

[/SUP]simplify on exponents
10[SUP]1/50[/SUP] =x[SUP]1/x

[/SUP]10[SUP]2/2*1/50[/SUP] =x[SUP]1/x[/SUP] note 2/2=1, so will not change the value of exponent
10[SUP]2(1/100)[/SUP] =x[SUP]1/x

[/SUP]100[SUP]1/100[/SUP] = x [SUP]1/x[/SUP]

x = 100
O-Level, Azania '96 - '99

mboni inaonekana kama copy and paste hiyo mzee hasa kuanzia hapo kwenye bluu