Chemsha ubongo wako

Chemsha ubongo wako

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Najua kwako hii ni hesabu rahisi sana, chemsha ubongo wako na unipe jibu fasta...


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Sorry engineer njia gani imetumika hapo?
Hapa nimetumia simultaneous equation
Example;
Let's call
Sungura = x
Mbwa = y and
Paka = z

Then;

x + z = 10................. eqn 1
y + x= 20..................... eqn 2
y+z=24......................... eqn 3

Take eqn 1 and make z the subject
y+z=10, z=10-z..............eqn 4

Substitute eqn 4 into eqn 2, gives
y+(10-z)=20, y-z=10...........eqn 5

Take eqn 3 and eqn 5
y-z=10
y+z=24
Take eqn 5 plus eqn 3 (either you can minus)
(y+y)+(-z+z)=10+24
2y = 34, divide 2 both sides, gives
y = 17
From eqn 2
y+x=20, make x the subject
x = 20 - y, substitute the value of y=17
x = 20 - 17 = 3
x = 3

From eqn 5
y - z = 10, but y = 17
17 - z = 10, z = 17 -10 =7
z = 7

Or from eqn 3
y + z = 24 but y = 17
17 + z = 24, z = 24 - 17 = 7

Then;
x + y + z = 3+ 17 + 7 = 27



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Hapa nimetumia simultaneous equation
Example;
Let's call
Sungura = x
Mbwa = y and
Paka = z

Then;

x + z = 10................. eqn 1
y + x= 20..................... eqn 2
y+z=24......................... eqn 3

Take eqn 1 and make z the subject
y+z=10, z=10-z..............eqn 4

Substitute eqn 4 into eqn 2, gives
y+(10-z)=20, y-z=10...........eqn 5

Take eqn 3 and eqn 5
y-z=10
y+z=24
Take eqn 5 plus eqn 3 (either you can minus)
(y+y)+(-z+z)=10+24
2y = 34, divide 2 both sides, gives
y = 17
From eqn 2
y+x=20, make x the subject
x = 20 - y, substitute the value of y=17
x = 20 - 17 = 3
x = 3

From eqn 5
y - z = 10, but y = 17
17 - z = 10, z = 17 -10 =7
z = 7

Or from eqn 3
y + z = 24 but y = 17
17 + z = 24, z = 24 - 17 = 7

Then;
x + y + z = 3+ 17 + 7 = 27



Sent using Jamii Forums mobile app
Kweli nilikuwa nimejichanganya nikafail
 
Hapa nimetumia simultaneous equation
Example;
Let's call
Sungura = x
Mbwa = y and
Paka = z

Then;

x + z = 10................. eqn 1
y + x= 20..................... eqn 2
y+z=24......................... eqn 3

Take eqn 1 and make z the subject
y+z=10, z=10-z..............eqn 4

Substitute eqn 4 into eqn 2, gives
y+(10-z)=20, y-z=10...........eqn 5

Take eqn 3 and eqn 5
y-z=10
y+z=24
Take eqn 5 plus eqn 3 (either you can minus)
(y+y)+(-z+z)=10+24
2y = 34, divide 2 both sides, gives
y = 17
From eqn 2
y+x=20, make x the subject
x = 20 - y, substitute the value of y=17
x = 20 - 17 = 3
x = 3

From eqn 5
y - z = 10, but y = 17
17 - z = 10, z = 17 -10 =7
z = 7

Or from eqn 3
y + z = 24 but y = 17
17 + z = 24, z = 24 - 17 = 7

Then;
x + y + z = 3+ 17 + 7 = 27



Sent using Jamii Forums mobile app
Nili'opt namba nkiwa std V baada ya kukutana na aljebra
Hapa nimetumia simultaneous equation
Example;
Let's call
Sungura = x
Mbwa = y and
Paka = z

Then;

x + z = 10................. eqn 1
y + x= 20..................... eqn 2
y+z=24......................... eqn 3

Take eqn 1 and make z the subject
y+z=10, z=10-z..............eqn 4

Substitute eqn 4 into eqn 2, gives
y+(10-z)=20, y-z=10...........eqn 5

Take eqn 3 and eqn 5
y-z=10
y+z=24
Take eqn 5 plus eqn 3 (either you can minus)
(y+y)+(-z+z)=10+24
2y = 34, divide 2 both sides, gives
y = 17
From eqn 2
y+x=20, make x the subject
x = 20 - y, substitute the value of y=17
x = 20 - 17 = 3
x = 3

From eqn 5
y - z = 10, but y = 17
17 - z = 10, z = 17 -10 =7
z = 7

Or from eqn 3
y + z = 24 but y = 17
17 + z = 24, z = 24 - 17 = 7

Then;
x + y + z = 3+ 17 + 7 = 27



Sent using Jamii Forums mobile app
Nili'opt namba nkiwa std V baada ya kukutana na aljebra....sa iz kutumiaga zaid +,-,× na ÷ tu

Sent using Jamii Forums mobile app
 
Soln.

Let m = mbwa
P = paka
S = sunguru.

Then

p + s = 10 .........i
m + s = 20..........ii
m + p = 24.........iii.

subtract ii - i

p - s = 4 .........iv
p + s = 10.

Then p = 7. s = 3. m = 17.

m+p+s = 17+ 7+3 = 27.



Sent using Jamii Forums mobile app
 
Hapa nimetumia simultaneous equation
Example;
Let's call
Sungura = x
Mbwa = y and
Paka = z

Then;

x + z = 10................. eqn 1
y + x= 20..................... eqn 2
y+z=24......................... eqn 3

Take eqn 1 and make z the subject
y+z=10, z=10-z..............eqn 4

Substitute eqn 4 into eqn 2, gives
y+(10-z)=20, y-z=10...........eqn 5

Take eqn 3 and eqn 5
y-z=10
y+z=24
Take eqn 5 plus eqn 3 (either you can minus)
(y+y)+(-z+z)=10+24
2y = 34, divide 2 both sides, gives
y = 17
From eqn 2
y+x=20, make x the subject
x = 20 - y, substitute the value of y=17
x = 20 - 17 = 3
x = 3

From eqn 5
y - z = 10, but y = 17
17 - z = 10, z = 17 -10 =7
z = 7

Or from eqn 3
y + z = 24 but y = 17
17 + z = 24, z = 24 - 17 = 7

Then;
x + y + z = 3+ 17 + 7 = 27



Sent using Jamii Forums mobile app
Hiyo ndio raha ya mathematics sasa,
 
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