Calculation of errors in resistance

Given R1=40 with tolerance of 3% and R2=30 with tolerance of 9% find total resistance

a) in series
b) in parallel

a) 73.8 or 66.1
b) 0.0548 or 0.0624

Nasubiri majibu

alibakari said:

a) 73.8

or 66.1

b) 0.0548

or 0.0624

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Njia?

Correction of errors

Napita hapo

Naja naja said:

Njia?

Click to expand...

Sheria ya kutafuta resistance zikiwa series unajumlisha [R1+R2+.......Rⁿ]

Sheria ya kutafuta resistance zikiwa parallel = R1+R2 Misha unagawanya kwa R1xR2

Mmmh

Hapo unatakiwa ujue dhana ya tolerance utapata jibu hesabu ndogo sana hiyo

In series Rs=(R1+R2)+(∆R1+∆R2)
=(40+30)+(0.03+0.09)
=(70+/-0.12)ohm

Naja naja said:

Given R1=40 with tolerance of 3% and R2=30 with tolerance of 9% find total resistance

a) in series
b) in parallel

Click to expand...

duyudu said:

In series Rs=(R1+R2)+(∆R1+∆R2)
=(40+30)+(0.03+0.09)
=(70+/-0.12)ohm

Click to expand...

In parallel
Apply natural logarithm to the equation ln Rp=ln(R1R2/Rs)
ln Rp=lnR1+lnR2-lnRs
Differentiate
∆Rp/Rp=∆R1/R1+..........kama hujaelewa nitafute mi nimechoka Ku type

Hizi ni hesabu za kujua ktk makinikia Kuna dhahabu kiasi gani?

duyudu said:

In parallel
Apply natural logarithm to the equation ln Rp=ln(R1R2/Rs)
ln Rp=lnR1+lnR2-lnRs
Differentiate
∆Rp/Rp=∆R1/R1+..........kama hujaelewa nitafute mi nimechoka Ku type

Click to expand...

Sijaelewa hiyo RS ndo nini?

Nyie fanyeni mahesabu, baadae mtaniletea vyombo vyenu niwatengenezee. Mimi ndio kiboko ya mambo ya resistor katika practice. Naangalia rangi ya michoro yake tu nishajua nguvu yake.

Rs=R1+R2

The tighter the tolerance the more stringent is the manufacturing process as regards material selection, production method , quality control. Tanzania ya viwanda inawezekana.