Makanyaga
JF-Expert Member
- Sep 28, 2007
- 10,327
- 6,850
Some Calculus solutions presented here (please see the PDF attachment below) are alternative corrected solutions from the Math24 website. The original solutions from the website appear as were wrongly computed using wrong limits of integration, thereby each giving a value of a region of integration as equal to zero. However, the fact is, the region of integration (be it area or volume) under any type of curve cannot be zero; it is always something bigger than zero.
The problems (and their URL) whose solutions have been corrected are as listed below
EXAMPLE 4 (Double Integrals over Rectangular Regions) (Double Integrals over Rectangular Regions - Page 2)
EXAMPLE 2 (Double Integrals in Polar Coordinates) (Double Integrals in Polar Coordinates)
EXAMPLE 3 (Double Integrals in Polar Coordinates) (Double Integrals in Polar Coordinates - Page 2)
However, where there may arise an oversight, I stand to be corrected and warmly welcome your valued contributions. Enjoy your reading
With kind regards
Makanyaga
The problems (and their URL) whose solutions have been corrected are as listed below
EXAMPLE 4 (Double Integrals over Rectangular Regions) (Double Integrals over Rectangular Regions - Page 2)
EXAMPLE 2 (Double Integrals in Polar Coordinates) (Double Integrals in Polar Coordinates)
EXAMPLE 3 (Double Integrals in Polar Coordinates) (Double Integrals in Polar Coordinates - Page 2)
However, where there may arise an oversight, I stand to be corrected and warmly welcome your valued contributions. Enjoy your reading
With kind regards
Makanyaga