Unapata zawadi nzuri ukipata jibu sahihi la hesabu hii ya calculus

[Makanyaga]

To all students and graduates;

QN: Integrate with respect to x: 1/lnx (one over natural logarithm of x)

 

[Mgogo Vitani]

Sent using Jamii Forums mobile app

 

[Hannah]

Hapo ndio swali tayari?

 

[Mokaze]

To all students and graduates;

QN: Integrate with respect to x: 1/lnx (one over natural logarithm of x)

The answer is:-

×/lnx+2lnx+c

 

[Upepo wa Pesa]

Hapo ndio swali tayari?

Unadhani swali lingekua refu kama maswali ya mfekane war?

 

[Makanyaga]

The answer is:-

×/lnx+2lnx+c

Hapana, siyo jibu lake. Umetumia njia gani kupata jibu hilo?

 

[Mtanzatozo]

itakuwa katumia njia ya nyerere kupata uhuru

 

[kimaku]

Nimekwama

 

[jooohs]

Kama uko advance huwezi hilo swali umeisha joking

Ila hapo ukiweza kuintegrate e* utakuwa umemaliza hilo swali
Sina uhakika na nilivyosolve ila uelekeo ndio huo huo maana ni kitambo sana

 

[steveachi]

Ngoja nimpigie sim yule dogo jiniaz wa jimboni kwa Tale

 

[Mokaze]

Hapana, siyo jibu lake. Umetumia njia gani kupata jibu hilo?

Kweli kuna mahali nilikosea, Subiri kidogo nilikalie kitako.

 

[Eng. Zezudu]

Kama uko advance huwezi hilo swali umeisha joking

Ila hapo ukiweza kuintegrate e* utakuwa umemaliza hilo swali
Sina uhakika na nilivyosolve ila uelekeo ndio huo huo maana ni kitambo sanaView attachment 1711681

Uko sawa Ila hapo ulipo fika kabla ya kufanya expansion ya e exponent u ilitakiwa utumie integration by part.

Sent using Jamii Forums mobile app

 

[Eng. Zezudu]

To all students and graduates;

QN: Integrate with respect to x: 1/lnx (one over natural logarithm of x)

Leta Ela nifanye integration faster Yani ,Mana me ndo chandi mwenyewe.

Sent using Jamii Forums mobile app

 

[mzalendo namba moja]

If ln(x) is 1/x.

But wait! How do we know that the derivative of ln(x) is 1/x? The if y=ln(x), then the derivative of ln(x) at x is the multiplicative inverse of the derivative of e^y at y. (Think about what happens to the slope of the tangent line when you swap the x and y axes.) In other words,
ddxln(x)=(ddyey)−1.ddxln⁡(x)=(ddyey)−1.
But we know that the derivative of e^y is just e^y, so the right-hand side simplifies to
(ey)−1=x−1=1x(ey)−1=x−1=1x.

But wait! How do we know that the derivative of e^y is e^y? Well, that's the definition of the exponential function (or a theorem, if you use a different definition for e)

 

[Makanyaga]

If ln(x) is 1/x.

But wait! How do we know that the derivative of ln(x) is 1/x? The if y=ln(x), then the derivative of ln(x) at x is the multiplicative inverse of the derivative of e^y at y. (Think about what happens to the slope of the tangent line when you swap the x and y axes.) In other words,
ddxln(x)=(ddyey)−1.ddxln⁡(x)=(ddyey)−1.
But we know that the derivative of e^y is just e^y, so the right-hand side simplifies to
(ey)−1=x−1=1x(ey)−1=x−1=1x.

But wait! How do we know that the derivative of e^y is e^y? Well, that's the definition of the exponential function (or a theorem, if you use a different definition for e)

Hili ni swali jingine au ni jibu kwa swali lililopo kwenye mada?

 

[mtzedi]

Ngoja nimpigie sim yule dogo jiniaz wa jimboni kwa Tale

Hana lolote yule dogo tofautisha hesabu na hisabati. Anachoweza ni hesabu.

 

[black short]

Kama uko advance huwezi hilo swali umeisha joking

Ila hapo ukiweza kuintegrate e* utakuwa umemaliza hilo swali
Sina uhakika na nilivyosolve ila uelekeo ndio huo huo maana ni kitambo sanaView attachment 1711681

Hako kaswali kameleta maelezo yote hayo?

 

[Lavit]

Advance nilipata B ila hapo hakuna ninachokumbuka hata kimoja..
Wakati enz hizo pure 1 na 2 zote zilikuwa kichwani

 

[jooohs]

Hako kaswali kameleta maelezo yote hayo?

Maelezo yapi ndugu?

 

[EllySkyWilly]

To all students and graduates;

QN: Integrate with respect to x: 1/lnx (one over natural logarithm of x)

Give me that money I'm waiting it.