Haya wale wa hesabu waanzie hapo...
A curve has parametric equations
x = 8e⁻²ᵗ - 4 and y = 2e²ᵗ + 4.
What is dx/dt?
Mamamaeeee hapo ilinichukua muda kweli kuzielewa..Differentiation na Integration
Is it dx/dt or dy/dx ??, if it is dx/dt then the answer is simply, -2(x+4). 🤣
Aseee hii ndio yenyewe kaka. Ni mwendo wa mambo ya psi tu,asee kwenye Kemia wakaigusa kidogo advance sema ndo hivo hawakuipa mkazo. Ila nakubali sana hiyo hesabu .Shrodinga equation.
Is it dx/dt or dy/dx ??, if it is dx/dt then the answer is simply, -2(x+4).
View attachment 2018100
The power doesn't change when you differentiate e²ᵗ.
Since the derivative of e^x is e^x
The derivative of 8e⁻²ᵗ is -2(8)e⁻²ᵗ
dx/dt = -16e⁻²ᵗ
Trick is to stick dx/dt ignore y = 2e²ᵗ + 4.