Naomba msaada wa kufanya hii hesabu

Simple tu.. Zidisha chin mara 4 na juu mara moja.. Then chukua ya chini toa ya juu..

Sina karatas ningesolve
 
Ziltan said:
karibuni wataalamu
Click to expand...
njoo kwetu said:
Simple tu.. Zidisha chin mara 4 na juu mara moja.. Then chukua ya chini toa ya juu..

Sina karatas ningesolve
Click to expand...
Kama hivyo sio
20210614_161609.jpg
 
Ziltan said:
solve by elimination
12/X + 15/Y =7
20/Y + 3/X = 3
Click to expand...
Fanya hivi:
By Elimination ina maana - epuka unknown moja = ua unkown mojawapo kati ya X au Y.
Hatua ya kwanza andika unknown zikae sawa (Arrange them) bila kuathiri thamani positive or Negative i.e.
12/x +15/y =7
3/x+20/y = 3
Then proceed kama ifuatavyo:
12/x + 15/y = 7 ni sawa na kusema 12/x = -15/y + 7 .......(i)
Pia 20/y +3/x = 3 ni sawa na kusema 3/x = = 3 - 20/y.........(ii)
Sasa pale palipoandikwa 12/x ,Original equation,badala yake andika hapo -15/y + 7; na pale palipoandikwa 3/x, original eqn. sasa andika hapo 3-20/y.
Kwa hiyo ;
kwa kuepuka kuandika au kutumia x sasa tunaweza kuandika
-15/y +7 i,e, nimeitumia hii badala ya kuandika 12/x.
vile vile 3-20/y = 3 badala ya kuandika 3/x.
Kwa hiyo:
(-15/y +7) + 15/y = 7 au ukipenda pia waweza andika 20/y + (3-20/y) = 3.
Sasa chagua kusolve mojawapo ya hizo One variable linear equations.
By removing brackets: -15/y + 7 + 15/y = 7
Pia 20/y+ (3-20/y) = 3
Therefore 20/y + 3 - 20/y = 3 and also -15/y +7+ 15/y =7
Katika eqn. No.(i) utapata 3=3 na eqn. No.(ii) 7=7 such equations are Undefined simultaneous equations or there is no single solution set.

Nawasilisha Mkuu.
 
Kirumberumbe said:
Fanya hivi:
By Elimination ina maana - epuka unknown moja = ua unkown mojawapo kati ya X au Y.
Hatua ya kwanza andika unknown zikae sawa (Arrange them) bila kuathiri thamani positive or Negative i.e.
12/x +15/y =7
3/x+20/y = 3
Then proceed kama ifuatavyo:
12/x + 15/y = 7 ni sawa na kusema 12/x = -15/y + 7 .......(i)
Pia 20/y +3/x = 3 ni sawa na kusema 3/x = = 3 - 20/y.........(ii)
Sasa pale palipoandikwa 12/x ,Original equation,badala yake andika hapo -15/y + 7; na pale palipoandikwa 3/x, original eqn. sasa andika hapo 3-20/y.
Kwa hiyo ;
kwa kuepuka kuandika au kutumia x sasa tunaweza kuandika
-15/y +7 i,e, nimeitumia hii badala ya kuandika 12/x.
vile vile 3-20/y = 3 badala ya kuandika 3/x.
Kwa hiyo:
(-15/y +7) + 15/y = 7 au ukipenda pia waweza andika 20/y + (3-20/y) = 3.
Sasa chagua kusolve mojawapo ya hizo One variable linear equations.
By removing brackets: -15/y + 7 + 15/y = 7
Pia 20/y+ (3-20/y) = 3
Therefore 20/y + 3 - 20/y = 3 and also -15/y +7+ 15/y =7
Katika eqn. No.(i) utapata 3=3 na eqn. No.(ii) 7=7 such equations are Undefined simultaneous equations or there is no single solution set.

Nawasilisha Mkuu.
Click to expand...
Asante sana Mkuu
ila natanguliza samahani kwan usahihi
wa swali hilo ni kama ifuatavyo:-
12/x + 15/y= 7
20/y - 3/x = 3
kwa watakaohitaji kujielimish lipo hivyo;
ila binafsi nashukur nimeshapat ufumbuz kam nilivyoweka hapo juu.
naomben mwongozo kwa haya maswali;
asanten sana.
20210614_182507.jpg
 
Ziltan said:
yap kw lile swali la kwnz"
bado hilo hapo chini; krb mkuu.View attachment 1818772
Click to expand...
1. (a) Haya ni maswali yanayolingana sana na ordinary one variable equations.
Solution iko hivi:
3x+4 = 25 and 3x + 4 > 25.
Then 3x + 4 = 25 utapata x= 7 na 3x + 4 > 7 utapata x > 7. Kwa hiyo solution ni All numbers real Numbers x grater than and including 7.
Chora numberline (x-axis) tu na onyesha namba 7 kwa kutumia dot n Bold kuanzia hapo na kuendelea upande wa +ve. Itaonekana hivi:

1623702375795.png
 
Kirumberumbe said:
Fanya hivi:
By Elimination ina maana - epuka unknown moja = ua unkown mojawapo kati ya X au Y.
Hatua ya kwanza andika unknown zikae sawa (Arrange them) bila kuathiri thamani positive or Negative i.e.
12/x +15/y =7
3/x+20/y = 3
Then proceed kama ifuatavyo:
12/x + 15/y = 7 ni sawa na kusema 12/x = -15/y + 7 .......(i)
Pia 20/y +3/x = 3 ni sawa na kusema 3/x = = 3 - 20/y.........(ii)
Sasa pale palipoandikwa 12/x ,Original equation,badala yake andika hapo -15/y + 7; na pale palipoandikwa 3/x, original eqn. sasa andika hapo 3-20/y.
Kwa hiyo ;
kwa kuepuka kuandika au kutumia x sasa tunaweza kuandika
-15/y +7 i,e, nimeitumia hii badala ya kuandika 12/x.
vile vile 3-20/y = 3 badala ya kuandika 3/x.
Kwa hiyo:
(-15/y +7) + 15/y = 7 au ukipenda pia waweza andika 20/y + (3-20/y) = 3.
Sasa chagua kusolve mojawapo ya hizo One variable linear equations.
By removing brackets: -15/y + 7 + 15/y = 7
Pia 20/y+ (3-20/y) = 3
Therefore 20/y + 3 - 20/y = 3 and also -15/y +7+ 15/y =7
Katika eqn. No.(i) utapata 3=3 na eqn. No.(ii) 7=7 such equations are Undefined simultaneous equations or there is no single solution set.

Nawasilisha Mkuu.
Click to expand...
mkuu hesabu uliishia ngazi gani? Samahani lakini.
 
Ziltan said:
solve by elimination
12/X + 15/Y =7
20/Y + 3/X = 3
Click to expand...
Let 1/x = a then 1/y = b
Hizo equations zitakuwa
12a +15b = 7
20b + 3a = 3
(Rearranging)
12a + 15b = 7.........(i)
3a + 20b = 3.........(ii)
Multiply eqn 1 by 3 and eqn 2 by 12.
36a + 45b = 21
36a + 240b = 36
Take eqn2 - eqn1
195b = 15
Divide by b both sides
b = 15/195
=1/13.
From eqn 1
36a + 45b = 21
36a = 21 - 45b
But b =1/13
36a = 21 - 45(1/13)
= 21 - 45/13
=228/13
36a = 228/13
a =(228/13)/36
a = 228/468
=19/39.
From above,
1/x = a
1/x =19/39 (make x the subject or just reciprocate both sides)
x = 39/19
Also
1/y = b
1/y = 1/13
y = 13
Therefore x = 39/19 and
y = 13.
Dah! Enzi zangu
 
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