# kwa wapenda mathematics wote!

Discussion in 'Jukwaa la Elimu (Education Forum)' started by deni, Sep 14, 2012.

1. ### deniSenior Member

#1
Sep 14, 2012
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Ni usiku wa manane. Kuna vijana wanne; A,B,C na D, wanahitaji kuvuka daraja lenye uwezo wa kuvusha watu wasiozidi wawili kwa wakati mmoja. Wote wanne wanahitajika wawe ng'ambo ya daraja baada ya dakika 17.. Kila mmoja ana speed yake ya kuvuka daraja: A yupo very fast anawezavuka kwa 1 min. B kwa 2 mins. C kwa 5 mins. D kwa 10 mins. Kama wakienda wawili alie fast hawez kumuharakisha alie slow kwahiyo speed itakayotumika ni ya slow. Pia kila wavukapo lazma wawe na tochi(tochi ipo moja). Mfano: A na D wakienda watatumia 10 mins na D akarudisha tochi,10mins jumla 20mins na watakua wamefeli. Je watavukaje kwa 17mins?

2. ### NarubongoJF-Expert Member

#2
Sep 15, 2012
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A= 1
B= 2+1
C= 5+1
D= 10

3+6+10 = 19 mins

3. ### QUALIFIEDJF-Expert Member

#3
Sep 16, 2012
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ukisikia msosi hakuna afu mbuzi kagoma kwenda ndio hii

4. ### venaJF-Expert Member

#4
Sep 16, 2012
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wasivuke na wachelewe wote! ngoma drooo
ukimwaga ugali namwaga unga.
mahesabu kaka najua ya pesa tu sio ya kuvusha daraja.

5. ### deniSenior Member

#5
Sep 17, 2012
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sasa kaka hii ndo nini?

6. ### nasssenMember

#6
Sep 17, 2012
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mkuu...ni lazma watumie 19 minutes!!!

7. G

### GinnerJF-Expert Member

#7
Sep 17, 2012
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mnavuka wenye speed tu..uyo anaetembea kwa maringo achaneni nae...anaishi kwa msemo there is no hurry in africa

8. ### deniSenior Member

#8
Sep 17, 2012
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hapana tatizo watu wanapokuwa wanawavusha hawo wanajikaririsha kwamba lazma mtu atakayerudisha tochi awe kati ya wale wawili walioenda! Hebu jaribu vizuri tena bila kujiwekea mipaka kama hiyo kama vipi tumia vijiti au vkaratasi kwa mfano wa watu!

9. ### NarubongoJF-Expert Member

#9
Sep 17, 2012
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mkuu unataka tuanze kuandika essay kwenye maths?

"Wote wanne wanahitajika wawe ng'ambo ya daraja" muonekano wa swali unaonesha initially wote wapo at same location and minimal time is 19 mins.. vinginevyo swali lako halijajitosheleza kimaelezo. Kwa assumption hiyo iwapo at least mmoja atakuwa at opposite direction ni lazima upate <=17 mins.

10. ### NarubongoJF-Expert Member

#10
Sep 17, 2012
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assume A yupo opposite na B, C, D na torch ipo kwa B, C, D
A= 1
B= 2
C= 5
D= 10

C&D + A + A&B
10+1+2= 13 mins

11. ### QUALIFIEDJF-Expert Member

#11
Sep 18, 2012
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kumbuka wote wanatakiwa wavuke daraja kwa mujibu wa maelezo yako A hajavuka daraja

12. ### n2braMember

#12
Sep 18, 2012
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hzi hesabu ckufundishwa

13. ### Mkaa MweupeJF-Expert Member

#13
Sep 18, 2012
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Kwa mujibu wa swali lako, hawawezi kuvuka chini ya dakika 17. Na only minimal time ni AD+A+AC+A+AB = 19 min.

14. ### simplemindJF-Expert Member

#14
Sep 18, 2012
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A na B wanavuka 2 min
A anarudisha torch 1 min
C na D wanavuka 10 min
B anarudisha torch 2 min
A na B wanavuka 2 min
jumla 17 min

15. ### NingaRJF-Expert Member

#15
Sep 18, 2012
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umetisha

16. ### NarubongoJF-Expert Member

#16
Sep 18, 2012
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oooh sawa mkuu nisahau ku+1

assume A yupo opposite na B, C, D na torch ipo kwa B, C, D
A= 1
B= 2
C= 5
D= 10

C&D + A + A&B + A [C na D wanavuka kwa 10mins halafu wanampa torch A ambaye atavuka kwa kutumia 1min, atamchukua B na watavuka kwa 2mins then A atarudi nga'mbo ya pili]
10+1+2+1= 14 mins [jumla ya muda watatumia]

17. ### deniSenior Member

#17
Sep 18, 2012
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kaka hapo umenoa C na D watampaje tochi A,ambaye yupo ngambo nyingine bila mmoja wao kuchukua muda wake na kuvuka kumpeleke tochi huyo A. Fanya ufanyalo dakika hazwez kupungua 17!

18. ### deniSenior Member

#18
Sep 18, 2012
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safi sanaa kaka!

19. ### deniSenior Member

#19
Sep 18, 2012
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Messages: 182