Dismiss Notice
You are browsing this site as a guest. It takes 2 minutes to CREATE AN ACCOUNT and less than 1 minute to LOGIN

Fanyeni hii intergration waungwana

Discussion in 'Jukwaa la Elimu (Education Forum)' started by JPM605, Sep 10, 2012.

  1. J

    JPM605 Senior Member

    #1
    Sep 10, 2012
    Joined: Aug 6, 2012
    Messages: 184
    Likes Received: 2
    Trophy Points: 35
    Nisaidieni 'intergral of the Squareroot of Sin X with respect to X' Ahsanteni.
     
  2. ProBook

    ProBook JF-Expert Member

    #2
    Sep 10, 2012
    Joined: Jan 13, 2012
    Messages: 327
    Likes Received: 26
    Trophy Points: 45
    Pure 2......
     
  3. King Kong III

    King Kong III JF-Expert Member

    #3
    Sep 10, 2012
    Joined: Oct 15, 2010
    Messages: 24,039
    Likes Received: 547
    Trophy Points: 280
    Cosx/2
     
  4. Mbwiga88

    Mbwiga88 JF-Expert Member

    #4
    Sep 10, 2012
    Joined: Jul 9, 2012
    Messages: 639
    Likes Received: 1
    Trophy Points: 35
    jaribu kutumia concept ya half angle
     
  5. B

    Boniface92 Member

    #5
    Sep 10, 2012
    Joined: Aug 13, 2012
    Messages: 61
    Likes Received: 0
    Trophy Points: 0
    taylor theorem
     
  6. K

    Kituko JF-Expert Member

    #6
    Sep 10, 2012
    Joined: Jan 12, 2009
    Messages: 5,924
    Likes Received: 1,073
    Trophy Points: 280
    Duh ndonga yangu imeshajaa maisha ambayo hayana uhusiano kabisa na hiyo intergration, enzi za mwalimu hiyo nilikuwa nakushukia kwa kichwa tu, haaaa ,,, SO MUCH SIMPLE
     
  7. Autorun

    Autorun JF-Expert Member

    #7
    Sep 10, 2012
    Joined: Mar 21, 2008
    Messages: 550
    Likes Received: 10
    Trophy Points: 35
    =-cos x+c
     
  8. ze duduz

    ze duduz JF-Expert Member

    #8
    Sep 10, 2012
    Joined: May 11, 2012
    Messages: 863
    Likes Received: 61
    Trophy Points: 45
    Nilikuwa CBG na nilikuwa nakula BAM Ila uwezo wa kupiga Banda la Pure Maths nilikuwa nao Xo jibu mpango mzma tumia taylor serie na jibu ni =x2/4-x4/64+c
    Note: x2 is x power 2 and x4 is x power 4
     
  9. Kijakazi

    Kijakazi JF-Expert Member

    #9
    Sep 10, 2012
    Joined: Jun 26, 2007
    Messages: 3,546
    Likes Received: 11
    Trophy Points: 135
    Nafikiri unaweza ukatumia Substitution method

    S (sinx) X (SinX) dx (S naitumia kama integral sign) hapo nimeexpand tu sin x squared
    halafu fanya substitution z= sinx
    z'= cos
    dz/dx=cosx
    dx= 1/cos dz
    Halafu unaweka kwenye sinx = z; S z (sinx)dx

    Baada ya hapo substutute dx; S z(sinx)1/sinx dz
    sinx na sinx zinajicancel unabakia na S z dz hapo sasa kazi imeisha unaintegrate tu z dz
    S z dz=1/2 z(squared) +C halafu unafanya resubstitution yaani pale pa z = sin x
    (sinx)squared/2 + C na hilo ndilo jibu lake (kumbuka nimetumia S kama integral sign!)
     
  10. f

    fortunho Senior Member

    #10
    Sep 11, 2012
    Joined: Aug 15, 2012
    Messages: 107
    Likes Received: 5
    Trophy Points: 35
    nimeamin hesabu sio mapishi.dogo fanya hivi,hauwezi ukapata exact answer na ndio maana wakilitoa huwaga wanaweka limits ilimradi utumie simpson au trapezoidal,akikuuliza aproxmat ans bila limit ndo unamkumbuka taylor.
     
  11. NingaR

    NingaR JF-Expert Member

    #11
    Sep 11, 2012
    Joined: Apr 15, 2012
    Messages: 2,827
    Likes Received: 8
    Trophy Points: 135
    kamawewe unajua hesabu tumia By-Part method then acha jibu katika 3 terms
     
  12. Ipycalypse

    Ipycalypse JF-Expert Member

    #12
    Sep 11, 2012
    Joined: May 25, 2011
    Messages: 3,062
    Likes Received: 1,586
    Trophy Points: 280
    Kumbe ulikua huamini.
     
  13. f

    fortunho Senior Member

    #13
    Sep 11, 2012
    Joined: Aug 15, 2012
    Messages: 107
    Likes Received: 5
    Trophy Points: 35
    haya bhana
     
  14. paul kitereja

    paul kitereja JF-Expert Member

    #14
    Sep 11, 2012
    Joined: Jun 15, 2012
    Messages: 264
    Likes Received: 1
    Trophy Points: 0
    tatizo hilo!
     
  15. J

    JPM605 Senior Member

    #15
    Sep 11, 2012
    Joined: Aug 6, 2012
    Messages: 184
    Likes Received: 2
    Trophy Points: 35
    Halina limits wala number of recquired ordinates hivyo naona trapezoidal na simpson zinafail..., haf tailor inaaply if f(x)=(x+a) kitu ambayo hii function haina.., kuhusu by parts nisaidieni ni ipi itakuwa U na dv?
     
  16. NingaR

    NingaR JF-Expert Member

    #16
    Sep 11, 2012
    Joined: Apr 15, 2012
    Messages: 2,827
    Likes Received: 8
    Trophy Points: 135

    S√sinx.dx
    Hapa hakuna ujanja zaidi ya kutumia By-Part method.
    ie. SVdU=UV-SUdV----eqn(a)
    let dU=dx
    Integrating both side
    =>U=x------eqn(i)
    and V=(sinx)^½
    differentiating both sides
    =>dV=(cosx)/(2√sinx)-------eqn(ii)
    Substituting ---eqn(i)&(ii) into --eqn(a)
    SVdU=x√sinx - 1/2S(xcosx)dx/(√sinx)
    For S(xcosx)dx/(√sinx)
    By By-Part tena
    SUdV=UV-SVdU
    Hapa let
    U=x
    =>dU=dx
    And
    dV=(cosx)/(√sinx)
    Integrating both sides
    =>V=2√sinx (kama hujaelewa hapo basi wewe ni kilaza)



    NIMECHOKA KUANDIKA
    NATHANI MTAKUA MMEPATA MWANGA
    (KAMA HUJUI HESABU KAA KUSHOTO)
     
  17. ze duduz

    ze duduz JF-Expert Member

    #17
    Sep 11, 2012
    Joined: May 11, 2012
    Messages: 863
    Likes Received: 61
    Trophy Points: 45
    teh teh kaka ulipata ngapi? Namba
     
  18. NingaR

    NingaR JF-Expert Member

    #18
    Sep 11, 2012
    Joined: Apr 15, 2012
    Messages: 2,827
    Likes Received: 8
    Trophy Points: 135
    Mkuu kwani VP??
     
  19. tindikalikali

    tindikalikali JF-Expert Member

    #19
    Sep 11, 2012
    Joined: Jan 14, 2011
    Messages: 4,887
    Likes Received: 63
    Trophy Points: 135
    Huna lolote wewe, ulijuaje kama ulikuwa na uwezo wa kupata banda? Pure siyo hizo BAM zenu
     
  20. NingaR

    NingaR JF-Expert Member

    #20
    Sep 11, 2012
    Joined: Apr 15, 2012
    Messages: 2,827
    Likes Received: 8
    Trophy Points: 135
    mkubwa swali ni integral ya √(sinX) sio integral ya sin²X
     
Loading...